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Nataly_w [17]
3 years ago
7

Can I have halp with all and an explanation because I am terrible at properties.

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
4 0
1.   4 • (–3) • 5
   so 4 x (-3) = -12  and then -12 x 5 = -60
2.   (2.25 x 23) x 4
so (2.25 x 23) 51.75  and then 51.75 x4 = 207
4.  5 x 12 x (-2)
 so 5 x 12 = 60  and then 60 x (-2) = -120
5.   35(26)(0) =
  so 35 x 26 = 910  and then  910 x 0 = 0

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This is not a multiple choice question. Please help!
Shkiper50 [21]
Complentary angle = 90 degrees
 
90 - 16 = your answer
5 0
3 years ago
Which are the correct steps for solving the equation ? Select all that apply
Radda [10]
I would love to help, but what are the options?
8 0
3 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
2 years ago
In the function f(x)=(x-2)^2+4, the minimum value occurs when x is
Vinil7 [7]

The graph of the function is a parabola. 

The nose comes down as far as y=4 but no farther.

That happens when  (x - 2)² = 0 , and THAT happens when x = 2 .

6 0
3 years ago
Read 2 more answers
write the equation of a line that passes through the points (5, -7) and is perpendicular to the line -2x + 6y = -4
VashaNatasha [74]

Answer:

y= -3x + 8

Step-by-step explanation:

Put -2x + 6y = -4 into slope-interceltp form

Take the negative reciprocal of the slope.

Use this reciprocal in point-slope form

and you have,

= y= -3x + 8

<em>(EDITED)</em> Steps:

2x+6y = -4

6y=2x - 4

y= 1/3x + 2/3

if two lines are perpendicular,

m1 * m2 + -1

1/3 * m2 = -1

m2 = -3

the line perpendicular to this line is

y = -3x + k ; k ∈ R

the line passes through the point (5,-7)

so,

-7 = -3. (5) +k

-7 = -15 + k

k = 8

∴the equation of a line that passes through the point (5,-7) and is perpendicular to the line -2x+6y=-4 is

y= -3x + 8

Hope this helps, have a nice day/night! :D

6 0
2 years ago
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