Question

write the equation of a line that passes through the points (5, -7) and is perpendicular to the line -2x + 6y = -4

Answer 1

Answer:

y= -3x + 8

Step-by-step explanation:

Put -2x + 6y = -4 into slope-interceltp form

Take the negative reciprocal of the slope.

Use this reciprocal in point-slope form

and you have,

= y= -3x + 8

(EDITED) Steps:

2x+6y = -4

6y=2x - 4

y= 1/3x + 2/3

if two lines are perpendicular,

m1 * m2 + -1

1/3 * m2 = -1

m2 = -3

the line perpendicular to this line is

y = -3x + k ; k ∈ R

the line passes through the point (5,-7)

so,

-7 = -3. (5) +k

-7 = -15 + k

k = 8

∴the equation of a line that passes through the point (5,-7) and is perpendicular to the line -2x+6y=-4 is

y= -3x + 8

Hope this helps, have a nice day/night! :D