All categories

3 years ago

Giving 20 points and please help

Mathematics

1 answer:

vlabodo [156]3 years ago

5 0

Hello,

Question- In the picture

Answer- The correct answer is A Because all you do is multiply buy 2 thats how simple it is.

Important- If my answer was enough to help you understand please mark me as brainliest thank you and have the best day ever!

You might be interested in

How many pennies are in 1 months lion dollars?

My name is Ann [436]

Ten thousand pennies

5 0

3 years ago

Read 2 more answers

X=4 in the equation e^lnx = 4. Why is this so? Can you go through the steps/rules

olga nikolaevna [1]

Answer:

e^(ln x) is just plain x

Step-by-step explanation:

The functions f(x) = e^x and g(x) = ln x are inverses of one another. In other words, one "undoes" the other.

Thus, as the rule goes, e^(ln x) is just plain x.

Here, e^(ln x) = 4 simplifies to x = 4.

7 0

3 years ago

4. Evaluate the expression for the given value of each variable.

Novosadov [1.4K]

Answer:

-18

Step-by-step explanation:

5a2-7-b3

$5*a*2-7-b*3$

$5\cdot \left(-2\right)\cdot \left(2\right)-7-\left(-3\right)\cdot 3$

Therefore, -18 is your answer.

Hope this helped! :)

5 0

3 years ago

The chance that you make a three-point shot in a basketball game is 30%. How many three-point shots would you expect to make if

Ganezh [65]

So 3 in every 10 would make it because 30% equals 3/10 and since there are 50 that would be 5 sets of 10. Thus 3*5=15. You would make 15 shots

4 0

3 years ago

manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe

Naddik [55]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32$

he then turns around and grabs that money and sticks it for another 9 years,

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64$

add both amounts, and that's how much is for the whole 21 years.

6 0

4 years ago