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Andre45 [30]
4 years ago
6

Simplify using the order of operations. 3/8-1/9

Mathematics
1 answer:
svetoff [14.1K]4 years ago
3 0

Answer:

19 /72 ≈0.264

Step-by-step explanation:

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For what value of y does 125=(1/25)^(y-1)?
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Answer:

y = -1/2 is the answer to 125=(1/25)^(y-1)

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the current temperature in smalltown is 20 degrees fahrenheit. this is 6 degrees less than twice the temperature that it was six
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The answer should be 4.

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A particular concentration of a chemical found in polluted water has been found to be lethal to 40% of the crayfish that are exp
Jet001 [13]

Answer:

a) P(X=13)=(24C13)(0.4)^{13} (1-0.4)^{24-13}=0.0608

P(X=17)=(24C17)(0.4)^{17} (1-0.4)^{24-17}=0.0017

P(X=13 U X=17) = 0.0608+0.0017=0.0624

b) P(X \geq 17)=0.000427

c) P(X \geq 16)= 1-0.000427=0.9996

d) E(X)= np = 22*0.4=8.8

e) Var(X) = np(1-p)= 22*0.4*(1-0,4)=5.28

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=24, p=0.4)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

3) Part a

P(X=13)=(22C13)(0.4)^{13} (1-0.4)^{22-13}=0.0336

P(X=17)=(22C17)(0.4)^{17} (1-0.4)^{22-17}=0.00035

P(X=13 U X=17) = 0.0336+0.00035=0.0340

4) Part b

P(X \geq 17)=P(X=17)+P(X=18)+P(X=19)+P(X=20)+P(X=21)+P(X=22)

P(X=17)=(22C17)(0.4)^{17} (1-0.4)^{22-17}=0.00035

P(X=18)=(22C18)(0.4)^{18} (1-0.4)^{22-18}=0.0000651

P(X=19)=(22C19)(0.4)^{19} (1-0.4)^{22-19}=0.00000914

P(X=20)=(22C20)(0.4)^{20} (1-0.4)^{22-20}=0.000000914

P(X=21)=(22C21)(0.4)^{21} (1-0.4)^{22-21}=5.81x10^{-8}

P(X=22)=(22C22)(0.4)^{22} (1-0.4)^{22-22}=1.76x10^{-9}

P(X \geq 17)=0.000427

5) Part c

P(X \leq 16)=1-P(X>16)=1-P(X\geq 17) = 1-[P(X=17)+P(X=18)+P(X=19)+P(X=20)+P(X=21)+P(X=22)]

P(X \geq 16)= 1-0.000427=0.9996

6) Part d

The expected value is:

E(X)= np = 22*0.4=8.8

7) Part e

The variance is given by:

Var(X) = np(1-p)= 22*0.4*(1-0,4)=5.28

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What is 5,254,071,926 written in standard form
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5.254071926×10^9
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