The distance that the yellow ball must travel after hitting the back wall to land in the pocket must be 45 inches.
Hope this helps.
I suppose the integral is
![\displaystyle\int_0^5\int_y^{\sqrt{25-y^2}} xy\,\mathrm dx\,\mathrm dy](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint_0%5E5%5Cint_y%5E%7B%5Csqrt%7B25-y%5E2%7D%7D%20xy%5C%2C%5Cmathrm%20dx%5C%2C%5Cmathrm%20dy)
The integration region corresponds to a sector of a cirlce with radius 5 subtended by a central angle of π/4 rad. We can capture this region in polar coordinates by the set
![R=\left\{(r,\theta)\mid0\le r\le5,0\le\theta\le\dfrac\pi4\right\}](https://tex.z-dn.net/?f=R%3D%5Cleft%5C%7B%28r%2C%5Ctheta%29%5Cmid0%5Cle%20r%5Cle5%2C0%5Cle%5Ctheta%5Cle%5Cdfrac%5Cpi4%5Cright%5C%7D)
Then
,
, and
. So the integral becomes
![\displaystyle\iint_Rxy\,\mathrm dx\,\mathrm dy=\int_0^{\pi/4}\int_0^5r^3\sin\theta\cos\theta\,\mathrm dr\,\mathrm d\theta=\frac{625}{16}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Ciint_Rxy%5C%2C%5Cmathrm%20dx%5C%2C%5Cmathrm%20dy%3D%5Cint_0%5E%7B%5Cpi%2F4%7D%5Cint_0%5E5r%5E3%5Csin%5Ctheta%5Ccos%5Ctheta%5C%2C%5Cmathrm%20dr%5C%2C%5Cmathrm%20d%5Ctheta%3D%5Cfrac%7B625%7D%7B16%7D)
The margin of error decreases with an increased sample size and increases with an increase in confidence level.
Speed: distance traveled in a given time
y=distance ( given in miles).
x = time (given in minutes)
Speed = y/x
y = 39.4x
By rearranging this y/x =39.4 ( is the constant speed). don’t forget this is mile/minutes
There are 4 x 60 minutes in 4 hours
Hence, you are asked the distance (y) in 240 min
y = 39.4x
y = 39.4 miles/minutes x (240) minutes
y = 9456 miles