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3 years ago

11

A salesperson is guaranteed $450 per week plus a 4% commission on all sales.

1 answer:

solong [7]3 years ago

5 0

$p\%=\dfrac{p}{100}\\\\4\%=\dfrac{4}{100}=0.04\\\\4\%\ of\ s\ dollars\ of\ sales\to0.04s\\\\An\ equation:\\\\\boxed{P=0.04s+450}$

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Can you help me i have only one day

tangare [24]

Answer:

n = -1.825

Step-by-step explanation:

8n + 16.2 = 1.6 (Given)

8n = -14.6 (Subtract 16.2 on both sides)

n = -1.825 (Divide 8 on both sides)

8 0

2 years ago

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A rectangle is 10 inches wider than it is long. The perimeter is 48 inches. what is the length and width of the rectangle?

Liula [17]

Answer:

a) x represents length?

b) 10+x=48

d) 38 inches

Step-by-step explanation:

c) 10+x=48

subtract 10 to both sides

x=48-10

x=38

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3 years ago

Calculate the simple interest on each amount and the total amount at the end.

Butoxors [25]

Attached is a picture of my answers.

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2 years ago

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

Add the integers.<br> -6 + (-4) =( ?<br> B-2<br> C 2<br> D 10

lina2011 [118]

Answer:
-6 + -4 = -10

3 0

3 years ago

Read 2 more answers