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Anna35 [415]
3 years ago
15

11. Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

Mathematics
1 answer:
azamat3 years ago
4 0

Answer:

Step-by-step explanation:

The first term is simply a(1), and is 5.

The fourth term is a(4), and is 5 + (1/6)(4-1), or 5  3/6  or 5 1/2.

The tenth term is a(10), and is 5 + (1/6)(10 - 1), or 5  + 3/2, or  6 1/2.

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Answer: (x+2)(2x-8)

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5 0
2 years ago
Gina's literacy bucket weighs 6 pounds. Her novel weighs 1 4/6 pounds, and her chrome book weighs 2 1/6 how much would her bucke
Paraphin [41]

Answer:

2\frac{1}{6} pounds.

Step-by-step explanation:

We have been given that Gina's literacy bucket weighs 6 pounds. Her novel weighs 1 4/6 pounds, and her chrome book weighs 2 1/6.

To find weight of bucket after taking out the two items, we will subtract weight of each item from 6 pounds as:

\text{Weight of bucket}=6-1\frac{4}{6}-2\frac{1}{6}

Let us convert mixed fractions into improper fractions as:

1\frac{4}{6}=\frac{6\cdot 1+4}{6}=\frac{10}{6}\\\\2\frac{1}{6}=\frac{6\cdot 2+1}{6}=\frac{12+1}{6}=\frac{13}{6}

\text{Weight of bucket}=6-\frac{10}{6}-\frac{13}{6}

\text{Weight of bucket}=\frac{6\cdot 6}{6}-\frac{10}{6}-\frac{13}{6}

\text{Weight of bucket}=\frac{36}{6}-\frac{10}{6}-\frac{13}{6}

Combine numerators:

\text{Weight of bucket}=\frac{36-10-13}{6}

\text{Weight of bucket}=\frac{13}{6}

\text{Weight of bucket}=2\frac{1}{6}

Therefore, the weight of the bucket is 2\frac{1}{6} pounds.

6 0
3 years ago
A basketball that sold for $55 is discounted 15%. what is the sale price?​
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Answer: $46.75

Step-by-step explanation:

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Total

15% of $55 =$8.25

$55.00 less $8.25

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3 years ago
What is the principal square root of StartRoot 13 Superscript 2 EndRoot.? 13 26 169 676
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Answer:

13

Step-by-step explanation:

If I read this correctly:

you want to know the square root of 13²?

That would be 13

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3 years ago
Need help on 12 and 11!! Hurry!!
jok3333 [9.3K]

11. 5/6

12.146/158=73/79

5 0
3 years ago
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