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zlopas [31]
3 years ago
15

Write an expression for the sequence of operations described below.

Mathematics
1 answer:
Sveta_85 [38]3 years ago
6 0
I believe that the expression would be t+(4+s)
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Jazz draws a transversal, t, on two parallel lines AB and CD, as shown below:
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I think it’s A. Hope this helped
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Which expression is equal to 0 when simplified?
aksik [14]
The answer is A) 2n-3m-(2n+3m)
6 0
3 years ago
Expand 5a(3a-2b). Thank you!
Thepotemich [5.8K]

Answer:

15 a^2 + -10 a b

Step-by-step explanation:

Expand the following:

5 a (-2 b + 3 a)

Hint: | Distribute 5 a over -2 b + 3 a.

5 a (-2 b + 3 a) = 5 a (-2 b) + 5 a (3 a):

-2 5 a b + 5 3 a a

Hint: | Combine products of like terms.

5 a×3 a = 5 a^2×3:

5×3 a^2 - 2×5 a b

Hint: | Multiply 5 and 3 together.

5×3 = 15:

15 a^2 - 2×5 a b

Hint: | Multiply 5 and -2 together.

5 (-2) = -10:

Answer: 15 a^2 + -10 a b

6 0
4 years ago
Read 2 more answers
A statistics practitioner determined that the mean and stan-dard deviation of a data set were 90 and 15, respectively. What can
jasenka [17]

Answer:

If the distribution is bell shaped we can approximate the probability with high accuracy using the z score formula.

a) P(75

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(75

b) P(60

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(60

c) P(45

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(45

If the distribution is NOT bell shaped the approximation with the z score NOT works and we need to have the distribution for X in order to find the probabilities.

Step-by-step explanation:

Previous concepts

If the distribution is bell shaped we can approximate the probability with high accuracy using the z score formula.

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable of interest

We assume for this case that \mu=90 and \sigma=15

We are interested on this probability

P(75

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(75

Part b

P(60

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(60

Part c

P(45

And for this case we can use the z score given by:

z = \frac{X-\mu}{\sigma}

And if we use it we got:

P(45

If the distribution is NOT bell shaped the approximation with the z score NOT works and we need to have the distribution for X in order to find the probabilities.

5 0
3 years ago
PLEASE HELP!!
Luba_88 [7]
10 is the answer hope it’s right papa bless
3 0
3 years ago
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