plz plz mark brainliest
============================================
Work Shown:
f(x) = 3x-1
f(x) = 3( x ) - 1
f( g(x) ) = 3( g(x) ) - 1 ... replace every x with g(x)
f( g(x) ) = 3(x^3-5x^2) - 1 ... plug in g(x) = x^3-5x^2
f( g(x) ) = 3x^3-15x^2-1
(f o g)(x) = 3x^3-15x^2-1
Answer:
Step-by-step explanation:
CD is Pole
∠CAD = 4° {Alternate interior angles}
ΔCAD,
In ΔCDB,
∠B = 5° {Alternate interior angles}
3x^2 − x − 4
factor
= (3x − 4)(x + 1)
answer
D. (3x − 4)(x + 1)
A. 2