Question

Need help asap, marking first as brainliest, would really appreciate it.

Answer 1

Answer:

B. One solution

Step-by-step explanation:

Here are a system of how two equations can be classified ;

• If the gradients are the same but the y-intercepts are different, the system has no solution.

• If the gradients are different, the system has one solution.

• If the gradients are the same and the y-intercepts are the same, the system has infinitely many solutions.

Y= (x/4) + 3

When x =1

y= 13/4

When x=3

y= 15/4

Gradient of Y= (x/4) + 3

=∆y/∆x

= (15/4 - 13/4)/ ( 3-1)

=( 2/4)÷ 2

=( 2/4 ) × (1/2)

= 1/4

-4x + y = 4

When x= 1

Y= 8

When x=3

Y=16

Gradient of -4x + y = 4

=∆y/∆x

= (16 - 8)/(3-1)= 8/2 = 4

Since the gradients are different then the system has one solution.