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Rina8888 [55]
3 years ago
9

Which is an equation of the inverse of y=3/2x?

Mathematics
1 answer:
Elenna [48]3 years ago
7 0

Answer:

y

=

3

2

x

Rewrite in slope-intercept form.

Tap for more steps...

y

=

3

2

x

Use the slope-intercept form to find the slope and y-intercept.

Tap for more steps...

Slope:  

3

2

y-intercept:  

(

0

,

0

)

Any line can be graphed using two points. Select two  

x

values, and plug them into the equation to find the corresponding  

y

values.

Tap for more steps...

x

y

0

0

2

3

Graph the line using the slope and the y-intercept, or the points.

Slope:  

3

2

y-intercept:  

(

0

,

0

)

x

y

0

0

2

3

image of graph

Step-by-step explanation:

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Circle P has a circumference of approximately 75 inches. Circle P with radius r is shown. What is the approximate length of the
Komok [63]

Answer:

12 inches, I hope this is right! :)

Step-by-step explanation:

circumference = 75 inches

75 / 2 = 35.7

37.5 / π = 11.9366207

Rounded to the nearest inch:

12 inches

8 0
3 years ago
Read 2 more answers
A tire has a radius of 13 inches. Which equation could be used to find the circumference of the tire
pav-90 [236]

Answer:

the tire should be 16 inches in diameter

a way that you can find diameter is if you are given the radius and you just multiply that number by 2 or ADD the same number because usually it is half of the diameter

6 0
2 years ago
The product of two factors is 7,200.if one of the factors is 90,what is the other factor?
Eddi Din [679]

Ok. Something times 90 = 7200.


Let something = x


90x = 7200


Divide both sides by 90.


90x/90 = 7200/90


x = 80


The other factor is 80.


5 0
3 years ago
irene works in a bakery. She uses 250 milliliters of milk to make a loaf of bread. how many liters of milk will she need to make
torisob [31]
You need to divied those numbers
8 0
3 years ago
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Given the vectors A⃗ and B⃗ shown in the figure ((Figure 1) ), determine the magnitude of B⃗ −A⃗. A is 28 degrees above the posi
Vlad [161]

This problem is represented in the Figure below. So, we can find the components of each vector as follows:


\bullet \ cos(28^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{A_{x}}{44} \\ \\ \therefore A_{x}=44cos(28^{\circ})=38.85m \\ \\ \\ \bullet \ sin(28^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{A_{y}}{44} \\ \\ \therefore A_{y}=44sin(28^{\circ})=20.65m


\bullet \ cos(56^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{-B_{x}}{26.5} \\ \\ \therefore B_{x}=-26.5cos(56^{\circ})=-14.81m \\ \\ \\ \bullet \ sin(56^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{B_{y}}{26.5} \\ \\ \therefore B_{y}=26.5sin(56^{\circ})=21.97m


Therefore:

\vec{A}=(38.85, 20.65)m \\ \\ \vec{B}=(-14.81, 21.97)m


So:

\vec{B}-\vec{A}=(-14.81, 21.97)-(38.85, 20.65)=(-53.66,1.32)


Finally, the magnitude is:


\boxed{\left| \vec{B}-\vec{A}\right|=\sqrt{(-53.66)^2+(1.32)^2}=53.67m}

7 0
3 years ago
Read 2 more answers
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