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2 years ago

BRAINLIEST TO WHOEVER ANSWERS FIRST!

Mathematics

1 answer:

densk [106]2 years ago

3 0

Answer:

Step-by-step explanation:

using N as the center and the same radius as before, draw an arc that intersects NO .Label the arc PQ where Q intersects NO.

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Please I need help on this question, A line passes through (6,3), (8,4), and (n,-2). Find the value of n.

Vika [28.1K]

Answer:

n= -4

Step-by-step explanation:

First we have to find the equation of line which passes through (6,3) and (8,4).

Then we have to pass this line through the point (n , -2).

we know, equation of line passing through (x1,y1) and (x2,y2) is

$\frac{x-x1}{x1-x2}=\frac{y-y1}{y1-y2}$

So, the equation of line passing through (6,3) and (8,4) is

$\frac{x-6}{6-8}=\frac{y-3}{3-4}$

or, $\frac{x-6}{-2} =\frac{y-3}{-1}$

multiplying both sides by -2

x-6=2(y-3)

or, x-6=2y-6

or, x-2y=6-6

or, x-2y=0

Now, we have to pass this line through (n,-2)

So, using the point in the line, that is using x=n , y=-2

we get

n-2(-2)=0

or, n+4=0

or, n=-4

6 0

3 years ago

Read 2 more answers

Can you find a math trick to play on a family member or friend? Be creative!

Makovka662 [10]

2x+3x=
X is simply a letter

6 0

3 years ago

At soccer practice, for every 5 minutes that Bob runs, e spends 20 minutes practicing dribbling. If Bob keeps the same ratio and

Kitty [74]

5/20=x/36

1/4=x/36

x=9

9 minutes.

8 0

3 years ago

The percent frequency for S&P 100 companies in the Consumer Staples sector is

torisob [31]

The percent frequency for S&P 100 companies in the Consumer Staples sector is 8.2%

<h3>How to determine the percentage frequency?</h3>

From the pie chart of the dataset (see attachment for the pie chart), we have:

Consumer Staples = 8.2%

This means that the percent frequency for S&P 100 companies in the Consumer Staples sector is 8.2%

Read more about pie charts at:

brainly.com/question/24461724

#SPJ1

8 0

2 years ago

Kamal wrote the augmented matrix below to represent a system of equations

ra1l [238]

Consider the operation is $R_2\to -3R_2$ .

Given:

The augmented matrix below represents a system of equations.

$\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]$

To find:

Matrix results from the operation $R_2\to -3R_2$ .

Step-by-step explanation:

We have,

$\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]$

After applying $R_2\to -3R_2$ , we get

$\left[\left.\begin{matrix}1&0&1\\-3(1)&-3(3)&-3(-1)\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-3(-9)\\-2\end{matrix}\right]$

$\left[\left.\begin{matrix}1&0&1\\-3&-9&3\\3&2&0\end{matrix}\right|\begin{matrix}-1\\27\\-2\end{matrix}\right]$

Therefore, the correct option is A.

3 0

3 years ago