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SashulF [63]
4 years ago
5

How do scientists use radioative decay to date fossils and artifacts

Physics
1 answer:
scZoUnD [109]4 years ago
5 0
ALL radioactivity matter has a set, unchanging, rate of decay. so if you measure the radioactive matter in an object, you can figure out how long it has been on the planet, based on what level of decay it is at.


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If pressure of a gas is increased in its volume at constant what will happen to its temperature
tresset_1 [31]

Answer:

Increase

Explanation:

If we assume the gas is ideal, then we can use the ideal gas law:

PV = nRT

If V is held constant while P increases, then T will also increase.

5 0
3 years ago
Read 2 more answers
A 100.0 mL sample of 1.020 M HCl is mixed with a 50.0 mL sample of 2.040 M NaOH in a Styrofoam cup. If both solutions were initi
I am Lyosha [343]

Answer:

t_2 = 33.793

Explanation:

Given data:

0.1 L HCl × 1.020 mol/L = 0.102 mol HCL

0.05 L NaOH × 2.040 mol/L = 0.102 mol NaOH

NaOH + HCl \rightarrow  H_2O + NaCl

0.102 mol HCl /1 mol HCl × 1 mol H2O = 0.102 mol H2O

0.102 mol H2O / 1 mol H2O × 57000 J = 5814 J

V(t ) = V_1+V_2 = 100 + 50 = 150 mL

M(t)=150*1=150 g

we know that heat energy is given as

Q = mc(t_2 - t_1)

where c is specific heat

total energy released is = 57 \times 0.102 = 5.814 kJ

5814 = 150 \times 4.184 \times (t_2 - 24.53)

t_2 = 33.793

8 0
4 years ago
Which of the following correctly describes the law of conservation of matter?
Tems11 [23]

Answer:

C

Explanation:

Tama Po yan don't worry

7 0
2 years ago
How can we determine the strength of a sonic boom?
tino4ka555 [31]
<span>There are several factors that can influence sonic booms - weight, size, and shape of the aircraft or vehicle, plus its altitude, attitude and flight path, and weather or atmospheric conditions.</span>
8 0
4 years ago
A rocket has landed on Planet X, which has half the radius of Earth. An astronaut onboard the rocket weighs twice as much on Pla
Burka [1]

Explanation:

Let acceleration due to Gravity for a planet is given by:

g_X=GM/R^2

Here,g_X = 2g

Escape velocity is given by:

v =\sqrt{ \frac{2GM} {R}} = \sqrt{2aR}

Here, R=R_earth/2

and g_X = 2g

Therefore,v=\sqrt(2(2g)(R/2))=v_0

7 0
3 years ago
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