Answer:
Time elapsed = 2.856
SECOND ROCK HAS FASTER SPEED
Explanation:
This can be achieved in 2 ways, and it is clear from the careful study that the travel time is attributed to the time required to cross the path above the bridge by the 2nd stone i.e.
14 = 9.8 * t
t = 1.428 sec and
time between 2 splash = 2 * 1.428 = 2. 857 sec
2nd way
let time for 1st spalsh be t and
second splash be t1.
from equation of motion
so 60 = 14t + 0.5 * 9.8 * t * t
4.9 t^2 + 14t -60 = 0
On solving, we get t = 2.351 sec
for t_1, we have some extra time, which can be divided into t2 and t3.
14 = 9.8 * t2
t2 = 1.428 sec
total time taken by 2 is
T = 1.428 + 1.428 + 2.351
so we get t_1 = 5.207 sec
time elapsed is = T - t
= 5.207 - 2.351
Time elapsed = 2.856
SECOND ROCK HAS FASTER SPEED
Given Information:
Diameter of the cylindrical tub = d = 50 cm = 0.50 m
Acceleration = α = 3g
Required Information:
1. Rotation rate in rev/min = ω = ?
2. Tangential speed in m/s = v = ?
Answer:
1. ω = 103.5 rev/min
2. v = 2.71 m/s
Explanation:
We know that centripetal acceleration is given by
α = ω²r
Where ω is the angular speed or rotation rate and r is the radius.
The relation between diameter and radius is given by
r = D/2
r = 0.50/2
r = 0.25 m
Since it is given that the acceleration is equal to 3g where g is the gravitational acceleration 9.81 m/s².
α = ω²r
3g = ω²r
ω² = 3g/r
ω = √(3g/r)
ω = √(3*9.81/0.25)
ω = 10.84 rad/s
To convert rad/s into rev/s divide it by 2π
ω = 10.84/2π
ω = 1.752 rev/s
To convert rev/s into rev/min multiple it by 60
ω = 1.752*60
ω = 103.5 rev/min
Therefore, the rotation rate is 103.5 rev/min
2. The tangential speed can be found using
v = ωr
Where ω is the rotation rate in rad/s and r is the radius.
v = 10.84*0.25
v = 2.71 m/s
Therefore, the tangential speed is 2.71 m/s
BEING HONEST , OPTIMISTIC,DISCIPLINED, PUNCTUAL ,TRUTHFUL AND GOOD ORATOR(SPEAKER) , AND HOPEFUL ARE OTHER BASIC QUALITIES AN EFFECTIVE LEADER MUST POSSESS. ALSO,HE MUST NEVER DIFFERENCE BETWEEN ANY OF HIS FOLLOWERS OR DO PARTIALLY AT ANY TIME . HE SHOULD TREAT EVERY ONE EQUALLY.
Explanation:
<span>TRUE
The force that opposes the movement of an object through water is called drag. This is a type of frictional force. This force normally depends on the density and the viscosity of the fluid in question. The liquid which has more density and more viscosity or stickiness will produce a greater amount of drag force on an object than a fluid that is less dense and less viscous in nature. River water normally has less drag than that of sea water. </span><span> <span>
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