Question

riders on the tower of doom, an amusement park ride, experience 2.0 s of free fall, after which they are slowed to a stop in 0.50 s . part a what is a 65 kg rider's apparent weight as the ride is coming to rest? express your answer to two significant figures and include the appropriate units.

Answer 1

By Newton's second law, the apparent weight of rider coming at rest is 3548 N.

According to formula, v = u + at

a = 39.2 m/$s^{2}$

Force, F = ma

F = m(a+g)

F = apparent weight

m = mass, given = 65 kg

a = acceleration, given = 39.2 m/$s^{2}$

g = 9.8 m/$s^{2}$

Put these values in formula, F = m(a+g)

F = 65(39.2+9.8)

F = 3548 N

Therefore, the apparent weight of rider coming at rest is 3548 N.

Learn more about apparent weight here:- brainly.com/question/24897276

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