Explanation :
A power amplifier is used to amplify electric signals i.e. to increase the low power signal to higher powers.
A PNP transistor is connected in a circuit so that the collector-base junction remains reverse biased and the emitter-base junction is forward biased.
This transistor can be used as a power amplifier because it gives a much larger output current. The gain of an amplifier shows the amount of amplification. It is the difference between the input and the output signals.
Answer:
is the current through the body of the man.
energy dissipated.
Explanation:
Given:
- time for which the current lasted,
![t=43\times 10^{-6}\ s](https://tex.z-dn.net/?f=t%3D43%5Ctimes%2010%5E%7B-6%7D%5C%20s)
- potential difference between the feet,
![V=21000\ V](https://tex.z-dn.net/?f=V%3D21000%5C%20V)
- resistance between the feet,
![R=550\ \Omega](https://tex.z-dn.net/?f=R%3D550%5C%20%5COmega)
<u>Now, from the Ohm's law we have:</u>
![I=\frac{V}{R}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7BV%7D%7BR%7D)
![I=\frac{21000}{550}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B21000%7D%7B550%7D)
is the current through the body of the man.
<u>Energy dissipated in the body:</u>
![E=I^2.R.t](https://tex.z-dn.net/?f=E%3DI%5E2.R.t)
![E=38.181^2\times 550\times 43\times 10^{-6}](https://tex.z-dn.net/?f=E%3D38.181%5E2%5Ctimes%20550%5Ctimes%2043%5Ctimes%2010%5E%7B-6%7D)
![E=34.5\ J](https://tex.z-dn.net/?f=E%3D34.5%5C%20J)
From rest, a rock is dropped from a garage roof. The roof is 6.0 meters above ground level. The rock will reach the earth at a speed of 10.849 meters per second.
<h3>What is velocity?</h3>
The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity.
it is a time-based component. Velocity at any angle is resolved to get its component of x and y-direction.
Given data:
V(Final velocity)=? (m/sec)
h(height)= 6.0 m
u(Initial velocity)=0 m/sec
g(gravitational acceleration)=9.81 m/s²
Newton's third equation of motion:
![\rm v_y^2 = u_y^2+ 2gh \\\\\rm v_y^2 = 0+ 2gh\\\\\ v_y= \sqrt{2\times 9.81 \ (m/s^2)\times 6.0 (m)} \\\\ v_y=10.849 \ m/sec](https://tex.z-dn.net/?f=%5Crm%20v_y%5E2%20%3D%20u_y%5E2%2B%202gh%20%5C%5C%5C%5C%5Crm%20v_y%5E2%20%3D%200%2B%202gh%5C%5C%5C%5C%5C%20%20v_y%3D%20%5Csqrt%7B2%5Ctimes%209.81%20%5C%20%28m%2Fs%5E2%29%5Ctimes%206.0%20%28m%29%7D%20%5C%5C%5C%5C%20v_y%3D10.849%20%5C%20m%2Fsec)
Hence, the velocity of the rock as it hits the ground will be 10.849 m/sec.
To learn more about the velocity refer to the link ;
brainly.com/question/862972
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