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hram777 [196]
3 years ago
5

PLS HELP ME W THIS QUESTION

Mathematics
1 answer:
QveST [7]3 years ago
7 0

Answer:

<h2>A. 60 in³</h2>

Step-by-step explanation:

The formula of a volume of a cone:

V=\dfrac{1}{3}\pi r^2H

r - radius

H - height

We have r = 1.9 in and H = 15 in. Substitute:

V=\dfrac{1}{3}\pi(1.9)^2(15)=\pi(3.61)(5)=18.05\pi\ in^3

\pi\approx3\to V\approx18.05\cdot3=54.15\ in^3

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(a) Five

(b) Thirteenth

Step-by-step explanation:

We have the mean is 12.6 and

that 11 occurs 4 times, 12 occurs 7 times, 13 occurs 9 times, and 14 occurs f times.

How many children are there in all (that is the sum of the frequencies).

4+7+9+f

20+f

Alright so the mean could be found by doing:

\frac{4(11)+7(12)+9(13)+f(14)}{20+f}

But we are given this is also equal to: 12.6.

So we have

\frac{4(11)+7(12)+9(13)+f(14)}{20+f}=12.6

I'm going to simplify what I can on top.

\frac{245+14f}{20+f}=12.6

I'm going to write 12.6 as \frac{12.6}{1} because I want to cross multiply:

\frac{245+14f}{20+f}=\frac{12.6}{1}

(245+14f)(1)=12.6(20+f)

Distribute:

245+14f=252+12.6f

Subtract 12.6f on both sides:

245+1.4f=252

Subtract 245 on both sides:

1.4f=7

Divide both sides by 1.4:

f=5

There are five 14 years old.

(b) I would say 13 is good age to represent this bunch.

The means was 12.6 which when rounded is 13.

The mode is 13 because it is the most occurring

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There are 4 eleven yr olds.

There are 7 twelve yr olds.  That is 11 kids so far.

So the median has to be included in the 9 thirteenth yr olds.

3 0
3 years ago
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