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enot [183]
3 years ago
13

How to solve equations with variables on both sides step by step?

Mathematics
1 answer:
USPshnik [31]3 years ago
5 0
2x+1=4x+6
-2x -2x

1=2x+6
-6 -6

-5=2x
/2. /2

-2.5=x

(This kind of equation?)
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Carina says that to divide by 12, she will need to write 12 as the fraction and then divide. Is she correct? Explain your reason
Alika [10]

Answer:

I do not know

Step-by-step explanation:

I think so

6 0
3 years ago
What is 2/3x+1=7? solve
butalik [34]
21X+7=2...........`\21X=2-7...........\ 21X=-5.............. X=-5÷21... this is the right answer..(x=-5÷21)
6 0
4 years ago
How to factor 6n2 - 6n - 12
alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

6n^2-6n-12 = 6(n^2-n-2)

We can set this equal to 0 and factor by using the quadratic formula which is:

x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

So, let's do just that:

6(n^2-n-2) = 0

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}

\frac{-1 \pm \sqrt{9} }{2} = {1, -2}

So, we can write this as:

6n^2 - 6n - 12 = 6(n-1)(n+2)

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

7 0
3 years ago
What is the range of the function f(x)=3x−1f(x)=3x-1 when the domain is {-1, 0, 1}?
Triss [41]
<span>f(x)=3x−1

</span><span>domain is {-1, 0, 1}

3(-1) -1 = -4
3(0) - 1 = -1
3(1) - 1 = 2

Range { -4,  -1,  2}</span>
4 0
3 years ago
Can someone please help me with this
Murljashka [212]
The answer is:  [C]:  "  2/3, 6/9, 8/12 " .
____________________________________________
4 0
4 years ago
Read 2 more answers
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