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4 years ago

Complete each nuclear fission reaction

Chemistry

1 answer:

r-ruslan [8.4K]4 years ago

8 0

Answer:

1. D = 222, E = 86

2. F = 234, G = 90

Explanation:Please see attachment for explanation

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Copper and silver are two examples of atoms that will form a(n) _____.

____ [38]

The answer is A. Copper and silver are two examples of atoms that will form a metallic bond. Pure metals in solid state form nets similar to crystals, but they are not ionic. The electrons of the valence shell are shared by all the atoms. The electrons can move freely in what is called a "sea of electrons" which is what confere metals the property of conducting electricity.

6 0

3 years ago

The product gas is then passed through a concentrated solution of KOH to remove the CO2. After passage through the KOH solution,

Kamila [148]

Answer: The mass percent of nitrogen gas in the compound is 13.3 %

Explanation:

Assuming the chemical equation of the compound forming product gases is:

$\text{Compound}\xrightarrow[CuO(s)]{Hot}N_2(g)+CO_2(g)+H_2O(g)$

Now, the product gases are treated with KOH to remove carbon dioxide.

We are given:

$p_{Total}=726torr\\P_{water}=23.8torr\\$

So, pressure of nitrogen gas will be = $p_{Total}-p_{water}=726-23.8=702.2torr$

To calculate the number of moles of nitrogen, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of nitrogen gas = 702.2 torr = 0.924 atm (Conversion factor: 1 atm = 760 torr)

V = Volume of nitrogen gas = 31.8 mL = 0.0318 L (Conversion factor: 1 L = 1000 mL)

T = Temperature of nitrogen gas = $25^oC=[25+273]K=298K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles of nitrogen gas = ?

Putting values in above equation, we get:

$0.924atm\times 0.0318L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\n_{mix}=\frac{0.924\times 0.0318}{0.0821\times 298}=0.0012mol$

To calculate the mass of nitrogen gas, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.0012 moles

Putting values in above equation, we get:

$0.0012mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.0012mol\times 28g/mol)=0.0336g$

To calculate the mass percent of nitrogen gas in compound, we use the equation:

$\text{Mass percent of nitrogen gas}=\frac{\text{Mass of nitrogen gas}}{\text{Mass of compound}}\times 100$

Mass of compound = 0.253 g

Mass of nitrogen gas = 0.0336 g

Putting values in above equation, we get:

$\text{Mass percent of nitrogen gas}=\frac{0.0336g}{0.253g}\times 100=13.3\%$

Hence, the mass percent of nitrogen gas in the compound is 13.3 %

8 0

4 years ago

Mercury is often used as an expansion medium in a thermometer. The Mercury sits in a bulb on the bottom of the thermometer and r

algol13

Just switch it to wumbo

4 0

3 years ago

How many carbon atoms are present in 3.900 x 10-4 mol of carbon? Give your answer in scientific notation. x 10 (select) A

AnnyKZ [126]

Answer: The number of atoms of carbon present in given number of moles are $2.350\times 10^{20}$

Explanation:

We are given:

Number of moles of carbon = $3.900\times 10^{-4}mol$

According to mole concept:

1 mole of an element contains $6.022\times 10^{23}$ number of atoms.

So, $3.900\times 10^{-4}mol$ of carbon will contain = $3.900\times 10^{-4}\times 6.022\times 10^{23}=2.350\times 10^{20}$ number of atoms.

Hence, the number of atoms of carbon present in given number of moles are $2.350\times 10^{20}$

4 0

3 years ago

Calculate the volume of an

yanalaym [24]

Answer:

9.0mm x 2.0mm x 2.0mm

= 18mm3

8 0

3 years ago