Correct Answer: CH2CCI2 and CH2CH2.
Reason:
Structure of compound depends on the hybridization of central atom. In both of the above molecules (i.e. CH2CCL2 and CH2CH2). Central atom i.e. carbon is sp^2 hybridized. Thus 3 hybridized orbitals of 'C' is involved in sigma bonding. Further, these orbitals are placed spatially at an angle of
. The un-hybridized 2pz orbital of 'C' is involved in pi-bonding. Due to this, both of the above molecules possess a triangular planner geometry.
Reason:
Structure of compound depends on the hybridization of central atom. In both of the above molecules (i.e. CH2CCL2 and CH2CH2). Central atom i.e. carbon is sp^2 hybridized. Thus 3 hybridized orbitals of 'C' is involved in sigma bonding. Further, these orbitals are placed spatially at an angle of