Answer:
0.019 g.
Explanation:
- Firstly, we need to find the no. of moles of oxygen gas:
- We can use the general law of ideal gas: <em>PV = nRT.
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where, P is the pressure of the gas in atm (P = 1.02 atm).
V is the volume of the gas in L (V = 15.0 L).
n is the no. of moles of the gas in mol (n = ??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 28°C + 273 = 301.0 K).
∴ n = PV/RT = (1.02 atm)(15.0 L)/(0.0821 L.atm/mol.K)(301.0 K) = 0.62 mol.
- To find the mass of oxygen gas, we have:
<em>no. of moles = mass/molar mass.</em>
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∴ mass of oxygen = (no. of moles)(molar mass) = (0.62 mol)(32.0 g/mol) = 0.019 g.
Talc is not a good choice when building a statue because the mineral Talc is one of the weakest minerals on the Mohs Scale with a hardness of 1 since it could be scratched by a fingernail, which means that when people build a statue with Talc, it could be easily broken down.
The Actinide series contains elements with atomic #'s 89 to 103 and is the sixth group in the periodic table. This series is below the Lanthanide series, which is located under the main body of the periodic table. Both Actinide and Lanthanide series are refered to as Rare Earth Metals. Hope this helped
Answer:
Solubilities of increases with increasing acidity
Explanation:
Concentration of decreases with increasing acidity. Therefore solubility of increases to keep constant solubility product.
Concentration of decreases with increasing acidity due to formation of . therefore solubility of ZnS increases to keep constant solubility product
Increasing acidity have no effect on this above equilibrium. Therefore solubility of remains constant.
Concentration of decreases with increasing acidity due to formation of . Therefore solubility of increases to keep constant solubility product.
Increasing acidity have no effect on this above equilibrium. Therefore solubility of NaI remains constant.
Concentration of decreases with increasing acidity due to formation of . Therefore solubility of increases to keep constant solubility product.