The pressure in the flask is 3.4 atm.
<em>pV</em> = <em>nRT
</em>
<em>T</em> = (20 + 273.15) K = 293.15 K
<em>p</em> = (<em>nRT</em>)/<em>V</em> = (1.4 mol × 0.082 06 L·atm·K⁻¹mol⁻¹ × 293.15 K)/10 L = 3.4 atm
4 is correct for this one
The answer is "More Stable."
Answer:
It has a thick atmosphere which causes extremely high temperatures.
Explanation:
The volume occupied by one mole of any gas at standard temperature(0o) and pressure(1 atm) is 22.4 litres. This volume is a close approximation and different gases vary slightly. The molar volume of any gas at S.T.P. is 22.4L .The mole of any gas can therefore be found using the expression on the right.
