The principal quantum number (n): specifies the principal shell of the orbital.
The answer is option D.
The important quantum number (n) describes the dimensions of the orbital. Orbitals for which n = 2 are larger than those for which n = 1, as an example. Because they have got opposite electric costs, electrons are interested in the nucleus of the atom.
The numerals, called essential quantum numbers, imply strength degrees as well as the relative distance from the nucleus. A 1s electron occupies the energy stage nearest the nucleus.
A 2s electron, less strongly certain, spends most of its time farther far from the nucleus.
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The titrant for this exercise. suppose Ca(OH)₂ were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. the analyte will still be HC₂H₃O₂. the stoichiometry ratio of HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.
The balanced reaction of the given condition as follow :
Ca(OH)₂ + 2HC₂H₃O₂ ------> Ca(C₂H₃O₂)₂ + 2H₂O
from the equation it is clear that stoichiometry of Ca(OH)₂ is 1 and the stoichiometry of HC₂H₃O₂ is 2. therefore the stoichiometry ratio of HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.
Thus, The titrant for this exercise. suppose Ca(OH)₂ were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. the analyte will still be HC₂H₃O₂. the stoichiometry ratio of HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.
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Answer:
See Explanation
Explanation:
Both oxygen and dinitrogen (1) oxide are known to rekindle a glowing splint. However, oxygen is an odorless gas while dinitrogen (1) oxide has a faint smell and has an effect on the central nervous system.
Also, the combustion of dinitrogen (1) oxide produces brown fumes of nitrogen IV oxide.
Finally, when dinitrogen (1) oxide and oxgen are both heated with copper, residual nitrogen gas is left with dinitrogen (1) oxide while no residual gas is left with oxygen.