Answer:
[ N₂(g) ] = 0.016 M
Explanation:
N₂(g) + 3 H₂(g) ↔ 2 NH₃(g)
The equilibrium constant for the above reaction , can be written as the product of the concentration of product raised to the power of stoichiometric coefficients in a balanced equation of dissociation divided by the product of the concentration of reactant raised to the power of stoichiometric coefficients in the balanced equation of dissociation .
Hence ,
Kc = [ NH₃ (g) ]² / [ N₂(g) ] [ H₂(g) ]³
From the question ,
[ NH₃ (g) ] = 0.5 M
[ N₂(g) ] = ?
[ H₂(g) ] = 2.0 M
Kc = 2
Now, putting it in the above equation ,
Kc = [ NH₃ (g) ]² / [ N₂(g) ] [ H₂(g) ]³
2 = [ 0.5 M ]² / [ N₂(g) ] [ 2.0 M ]³
[ N₂(g) ] = 0.016 M .
7.2 * 10^23 molecules CO2 1 mole CO2
x ___________________
6.02* 10^23 molecules CO2
=1.196
=1.2 moles of CO2
Your answer should be B.. i am not 100%
The answer is
You must make sure each reactant has the same amount of subscripts on both sides of the equation.
