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Stels [109]
3 years ago
5

how to find percent composition of a compound composed of 16.2 grams of calcium and 28.8 grams of chlorine

Chemistry
1 answer:
Leto [7]3 years ago
7 0

This problem is providing us with the mass of calcium and chlorine. Thus, the percent composition of each element in the compound is required and found to be 36 % for calcium and 64 % for chlorine, according to the following:

<h3>Percent compositions:</h3>

In chemistry, we can use percent compositions in order to find a relationship between the relative amount of the elements in a compound and the mass of the very same compound.

In this case, given the mass of each element (chlorine and calcium), one can simply divide it by the sum of the masses of both calcium and chlorine to obtain the following:

\% Ca=\frac{16.2g}{16.2g+28.8g}*100\%= 36\%\\\\\% Ca=\frac{28.8g}{16.2g+28.8g}*100\%= 64\%\\

Learn more about percent composition: brainly.com/question/12247957

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garri49 [273]

1 in 10, or 1/10, or 0.1 dilution factor It may be wrong but this is what I have!

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3 years ago
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If water is present during the grignard formation, what possible byproduct may form?
Zanzabum

Important of Grignard Reagent :

Grignard reactions are main due to their capacity to form carbon-carbon bonds. Grignard reagents are powerful bases and will react with protic compounds which makes them exceptionally valuable implement for organic synthesis.

Grignard reagents react fastly with acidic hydrogen atoms in molecules such as alcohols and water. When a Grignard reagent reacts with water, a proton return back halogen, and the product is an alkane. The Grignard reagent therefore provides a trace for transforming a haloalkane to an alkane in two steps.

When reacted with water,

RMgX + H2O -------> R-H + MgOH X

R ---- Alkyl Group

X --- Halogen

To know more about Grignard Reagent here :

brainly.com/question/15876201?referrer=searchResults

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4 0
2 years ago
3. If x electrons are needed to displace 108 g silver from a solution which contains Ag ions,
ss7ja [257]

Answer:

Choice A. x electrons would be required for displacing 9\; \rm g of aluminum from a solution of \rm Al^{3+} ions.

Assumption: by "\rm Ag ions" the question meant \rm Ag^{+} with a charge of +1 on each ion.

Explanation:

The question states that the relative atomic mass of \rm Ag is 108. In other words, each mole of

Therefore, that 108\; \rm g\! of silver that were formed would contain 1\; \rm mol of silver atoms.

Metallic silver would precipitate out of this \rm Ag^{+} solution only after these ions are turned into \rm Ag atoms.

One \rm Ag^{+} ion carries one unit of positive electrical charge. On the other hand, each  e^{-} carries one unit of negative electrical charge.

Therefore, each \rm Ag^{+}\! ion will need to gain one electron to form a neutral \rm Ag atom.

{\rm Ag^{+}}\; (aq) + e^{-} \to {\rm Ag}\; (s).

At least  1\; \rm mol of electrons would be required to turn 1\; \rm mol\! of \rm Ag^{+} ions into that 1\; \rm mol\!\! of silver atoms (which have a mass of 108\; \rm g\!.)

Hence, x = 1\; \rm mol.

Unlike \rm Ag^{+} ions, each aluminum ion \rm Al^{3+} carries three units of positive electrical charge. That is three times the amount of charge on one \rm Ag^{+}\! ion. Therefore, three electrons will be required to turn one \rm Al^{3+}\! ion to an \rm Al atom.

{\rm Al^{3+}}\; (aq) + 3\, e^{-} \to {\rm Al}\; (s)

The question states that the relative atomic mass of \rm Al is 27. Therefore, each mole of \rm Al\! atoms would have a mass 27\; \rm g. There would be \displaystyle \frac{9\; \rm g}{27\; \rm g \cdot mol^{-1}} = \frac{1}{3} \; \rm mol of atoms in that 9\; \rm g of \rm Al\!\!.

It takes 3\; \rm mol of electrons to turn one mole of \rm Al^{3+} ions to one mole of \rm Al atoms. Hence, \displaystyle \frac{1}{3}\times 3\; \rm mol = 1\; \rm mol of electrons would be required to produce that \displaystyle \frac{1}{3}\; \rm mol of \rm Al\! atoms (which has a mass of 9\; \rm g) from \rm Al^{3+}\! ions.

That corresponds to the first choice, x electrons.

7 0
3 years ago
Ann drove to the store km north of her house and then drove to the library, which is 5 km south of the store. She drove a total
Vadim26 [7]
Answer : The question is incomplete, the complete question is attached in answer

To calculate the displacement by Ann's driving from north of her house to south;

we have the data as 

In north - 10 km
in south - 5 km
total - 15 km

So we can calculate the displacement, which will be,

10 - 5 = 5 km.

Hence, the displacement will be 5 km 


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It is E. because the predators will have slightly more meals with their prey slightly increasing population.
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