Answer:
volatility means liability to change rapidly and unpredictably, especially for the worse
Answer:
![\large\boxed{0.019\, \mu \text{mol/L}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B0.019%5C%2C%20%5Cmu%20%5Ctext%7Bmol%2FL%7D%7D)
Explanation:
![\text{Concentration } = \dfrac{\text{moles}}{\text{litres}}\\\\\text{c} = \dfrac{n}{V}](https://tex.z-dn.net/?f=%5Ctext%7BConcentration%20%7D%20%3D%20%5Cdfrac%7B%5Ctext%7Bmoles%7D%7D%7B%5Ctext%7Blitres%7D%7D%5C%5C%5C%5C%5Ctext%7Bc%7D%20%3D%20%5Cdfrac%7Bn%7D%7BV%7D)
1. Convert millilitres to litres
![\text{V = 350. mL} \times \dfrac{\text{1 L}}{\text{1000 mL}} = \text{0.3500 L}](https://tex.z-dn.net/?f=%5Ctext%7BV%20%3D%20350.%20mL%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20L%7D%7D%7B%5Ctext%7B1000%20mL%7D%7D%20%3D%20%5Ctext%7B0.3500%20L%7D)
2. Calculate the concentration
![c = \dfrac{0.0067\, \mu\text{mol}}{\text{0.3500 L}} = \mathbf{0.019 \, \mu}\textbf{mol/L}\\\\\text{The concentration of mercury(II) iodide is $\large\boxed{\mathbf{0.019\, \mu} \textbf{mol/L}}$}.](https://tex.z-dn.net/?f=c%20%3D%20%5Cdfrac%7B0.0067%5C%2C%20%5Cmu%5Ctext%7Bmol%7D%7D%7B%5Ctext%7B0.3500%20L%7D%7D%20%3D%20%5Cmathbf%7B0.019%20%5C%2C%20%20%5Cmu%7D%5Ctextbf%7Bmol%2FL%7D%5C%5C%5C%5C%5Ctext%7BThe%20concentration%20of%20mercury%28II%29%20iodide%20is%20%24%5Clarge%5Cboxed%7B%5Cmathbf%7B0.019%5C%2C%20%5Cmu%7D%20%5Ctextbf%7Bmol%2FL%7D%7D%24%7D.)
Answer:
ratio is 5Fe2+/1KMnO4
Explanation:
You can find the ratio using the coefficients of the known and unknown variables. This will shift the answer for your calculations so make sure to include it. without the mole ratio step, you can not compare 2 molecules or elements.
Answer:
165.52 g/mol
Explanation:
Upon temperature was raised to 100 C part of the initial mass of liquid is gas, exactly: 2.00-0.581 = 1.419 g. This gas occupy a volume of approximately 265 mL, its pressure of 752 mm Hg and its temperature is 100 C. Assuming that this gas behaves as gas ideal we can estimate the molecular weight
taking into account tha gas ideal law:
with R= 0.082 atm L/(mol K)
or ![M_{W}=\frac{RTm}{PV}](https://tex.z-dn.net/?f=M_%7BW%7D%3D%5Cfrac%7BRTm%7D%7BPV%7D)
Before using of the formula, we need convert volume units to L (1L=1000 mL) pressure to atm (1 atm=760 mmHg) and temperature to K (K=273+C).
![752/760=0.989 atm](https://tex.z-dn.net/?f=752%2F760%3D0.989%20atm)
![273+100=373 K](https://tex.z-dn.net/?f=273%2B100%3D373%20K)
Finally, replacing in the formula
g/mol