Find the range of the glven data set.<br> -4,-3,-1,-1, 0, 1

A number expressible in the form a/b where a and b are integers

Marta_Voda [28]

Answer:

Step-by-step explanation:

Rational Numbers are defined as set of numbers that can be written as a/b.

where,

a and b are integers, but b is not equal to 0; an integer or a fraction.

Also, a rational number is a number that is expressed as the quotient or fraction a/b of two integers, where a numerator a and a non-zero denominator b is found. Since a may be equal to 1, every integer is a rational number.

3 0

3 years ago

Super confused definitely need help on this

Marat540 [252]

Answer:

$(x-5)(x+8)=x^2+3x-40$

Step-by-step explanation:

So we have the expression:

$(x-5)(x+8)$

To multiply, distribute the left to the terms on the right:

$=(x-5)(x)+(x-5)(8)$

Distribute:

$=(x^2-5x)+(8x-40)$

Combine like terms:

$=(x^2)+(-5x+8x)+(-40)$

Simplify:

$=x^2+3x-40$

Therefore:

$(x-5)(x+8)=x^2+3x-40$

6 0

3 years ago

Read 2 more answers

Help. and please show workout so I can know how to understand it (and both questions)

Arlecino [84]

Just remove the parenthesis since you are adding them and combine like terms
x+5+2x+3
3x+8

8 0

3 years ago

5. Let A = (x, y), B = {1,2). Find the Cartesian products of A and B: A x B? (Hint: the result will be a set of pairs (a, b) whe

hichkok12 [17]

Answer: A x B = {(x,1), (x,2), (y,1), (y,2)}

Step-by-step explanation:

The Cartesian product of any two sets M and N is the set of all possible ordered pairs such that the elements of M are first values and the elements of N are the second values.

The Cartesian product of sets M and N is denoted by M × N.

For Example : M = {x,y} and N={a,b}

Then , M × N ={(x,a), (x,b), (y,a), (y,b)}

Given : Let A = {x, y}, B = {1,2}

Then , the Cartesian products of A and B will be :

A x B = {(x,1), (x,2), (y,1), (y,2)}

Hence, the Cartesian products of A and B = A x B = {(x,1), (x,2), (y,1), (y,2)}

8 0

3 years ago

If Upper X overbar equals 62, Upper S equals 8, and n equals 36, and assuming that the population is normally distributed, c

marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=62$ represent the sample mean

$\mu$ population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=36-1=35$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that $t_{\alpha/2}=2.72$

Now we have everything in order to replace into formula (1):

$62-2.72\frac{8}{\sqrt{36}}=58.373$

$62+2.72\frac{8}{\sqrt{36}}=65.627$

So on this case the 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

3 0

3 years ago

Find the range of the glven data set. -4,-3,-1,-1, 0, 1