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agasfer [191]
3 years ago
8

The angle of depression from the basketball hoop to Clairs eyes is 9.2degrees. The vertical distance from the ground to Claires

eyes is 5.6 feet. Using the diagram, find the height of the basketball hoop to the nearest tenth.
Mathematics
2 answers:
Norma-Jean [14]3 years ago
8 0
X - difference between the height of the basketball hoop and the vertical distance from the ground to Clair´s eyes.
Using T O A:
tan (9.2°) = x / 22 ft
x = tan (9.2°) · 22 ft
x = 0.162 · 22 ft 
x = 3.564 ft
The height of the basketball hoop is:
h = 5.6 + 3.564 = 9.164 feet
natulia [17]3 years ago
5 0

Answer:

the answer is C

Step-by-step explanation:

i just took the test

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A

Step-by-step explanation:

Hope it helps!

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2 years ago
Will mark BRAINLIST for only correct answer
katovenus [111]

Answer:

Gym A

Step-by-step explanation:

A linear relationship is a relationship of the form y = mx + b, where y and x are the linear variables, m is the rate of change and b is the value of y when x = 0.

Gym A:

Let x represent the month and y represent the total cost for the gym. From the table, we can represent the values in the form (x, y) as (1,70), (2, 90) and (3, 110). We can find the relationship between x and y using the formula:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\Let \ us\ use\ the\ points\  (1,70)\ and\ (3,110),hence:\\\\y-70=\frac{110-70}{3-1}(x-1)\\\\y-70=20(x-1)\\\\y=20x-20+70 \\\\y=20x+50\\\\For\ 10\ months(i.e.\ x=10):\\\\y=20x+50\\\\y=20(10)+50\\\\y=\$250

Gym B:

We can represent the values from the table as (1,55), (2, 80) and (3, 105). We can find the relationship between x and y using the formula:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\Let \ us\ use\ the\ points\  (1,55)\ and\ (3,105),hence:\\\\y-55=\frac{105-55}{3-1}(x-1)\\\\y-55=25(x-1)\\\\y=25x-25+55 \\\\y=25x+30\\\\For\ 10\ months(i.e.\ x=10):\\\\y=25x+30\\\\y=25(10)+30\\\\y=\$28 0

Hence gym A would cost less ($250 < $280)

4 0
3 years ago
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Answer:

a=-2

Step-by-step explanation:

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3 years ago
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Answer:

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