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3 years ago

What's the algebraic expression of "4 times a number cubed decreased by 7"?

Mathematics

2 answers:

Maksim231197 [3]3 years ago

5 0

Answer:

Statement: "4 times a number cubed decreased by 7"

Let a number be x is denoted as an arbitrary variable.

Now, cubed means raise x to the third power i.e $x^3$

then, 4 times a number cubed i.e $4x^3$

Decreased by 7 means, subtract 7

⇒ $4x^3-7$

Therefore, the algebraic expression for the given statement is, $4x^3-7$

Likurg_2 [28]3 years ago

4 0

Take the variable to be x

4x^3-7

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Factor 2x^2 - 50 completely.

alekssr [168]

Answer:

The answer is C

Step-by-step explanation:

There are 2 X's therefore there will be two sets of quotations with one X in each. Then find the multiples of 50.

Try -5 and +5 go in with the x which makes the answer C

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3 years ago

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Which ordered pair is a solution of this

Natalija [7]

Answer:

(-1, -2)

Step-by-step explanation:

when x = -1 and y = -2,

(-2 · -1) - (-2) = 2 + 2 = 4

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2 years ago

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The mean waiting time at the drive-through of a fast-food restaurant from the time the food is ordered to when it is received is

alexira [117]

Answer:

a) And if we replace we got: $\bar X= 78$

$s = 15.391$

b) $78-3.25\frac{15.391}{\sqrt{10}}=62.182$

$78-3.25\frac{15.391}{\sqrt{10}}=93.818$

So on this case the 99% confidence interval would be given by (62.182;93.818)

Step-by-step explanation:

Dataset given: 109 67 58 76 65 80 96 86 71 72

Part a

For this case we can calculate the sample mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got: $\bar X= 78$

And the deviation is given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And if we replace we got $s = 15.391$

Part b

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,9)".And we see that $t_{\alpha/2}=3.25$

Now we have everything in order to replace into formula (1):

$78-3.25\frac{15.391}{\sqrt{10}}=62.182$

$78-3.25\frac{15.391}{\sqrt{10}}=93.818$

So on this case the 99% confidence interval would be given by (62.182;93.818)

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2 years ago

What are the zeroes of P(x) = x3 – 6x2 - x +62

Maurinko [17]

Answer:

x = 6

x = -1

x = 1

Step-by-step explanation:

Given:

Correct equation;

P(x) = x³ - 6x² - x + 6

Computation:

x³ - 6x² - x + 6

x²(x-6)-1(x-6)

(x-6)(x²-1)

we know that;

a²-b² = (a+b)(a-b)

So,

(x-6)(x²-1)

(x-6)(x+1)(x-1)

So,

zeroes are;

x = 6

x = -1

x = 1

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3 years ago

Find the values of x and y. 107<br> X= y=

Debora [2.8K]

Answer:

y= 73 degrees

x=34 degrees

Step-by-step explanation:

180-107=73

y= 73 degrees

73+73= 146

180-146=34

x=34 degrees

8 0

2 years ago