EXPRESS THE SOLUTION AS AN INEQUALITY

Ben,is,repacking a 45 pound bag of rice into 8,smaller bags. How much rice is going to be in each smaller bag

DIA [1.3K]

5.625 pounds in each bag.

7 0

3 years ago

Pam and Meg each have a picture frame. Pam’s picture frame is a square with an area of 3 square feet. Meg’s picture frame is a c

kondaur [170]

Answer:

The circumference of Meg’s picture frame is the perimeter of Pam’s picture frame by approximately 0.65 ft

Step-by-step explanation:

Pam's picture frame : Square with area of 3 sq. foot

Meg’s picture frame is a circle with a radius, r of 1 foot.

The circumference of Meg’s picture frame is the perimeter of Pam’s picture frame by approximately feet.

Let's calculate circumference of Meg's picture frame:

Circumference c, = 2πr

r = 1 ft

c = 2 * 3.14 *1 = 6.28 ft

Now calculate Perimeter of Pam's picture frame:

A is area of square and s is the side

A = s²

s² = 3

s = √3

Permeter of square = 4s

= 4√3 = 6.93ft

Now in order to find circumference of Meg’s picture frame is the perimeter of Pam’s picture frame, we have to find their difference.

Permimeter of square frame - Circumference of circle frame = 6.93 - 6.28 = 0.65

8 0

3 years ago

If point F is translated 6 units to the right and 5 units up , what are the coordinates of F'?

patriot [66]

Answer:

Where is F to begin with? If F is at (0,0), then F' will be (6,5) But if F is at (3,-5), F' will be at (9,0).

<h2>Step-by-step explanation: Can i have brainliest pls</h2>

5 0

3 years ago

Read 2 more answers

he Nassau Bahamas Community College (NBC) claims that students who take statistics spend on average 19 hours a week working. The

Virty [35]

Using the t-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that the students' claim that they work more than 19 hours is correct.

At the null hypothesis, it is tested if they spend on average 19 hours a week working, that is:

$H_0: \mu = 19$

At the alternative hypothesis, it is tested if they spend more than 19 hours a week working, that is:

$H_1: \mu > 19$

We have the standard deviation for the sample, hence, the t-distribution is used.

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

Searching the problem on the internet, it is found that the values of the parameters are:

$\overline{x} = 24.2, \mu = 19, s = 12.59, n = 25$

Hence, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{24.2 - 19}{\frac{12.59}{\sqrt{25}}}$

$t = 2.07$

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05 and 25 - 1 = 24 df is of $t^{\ast} = 1.71$

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that the students' claim that they work more than 19 hours is correct.

To learn more about the t-distribution, you can take a look at brainly.com/question/13873630

3 0

3 years ago

The total area of the figure to the right is 299 cm². Use this fact to write an equation involving x. Then solve the

Sliva [168]

Answer:

i. $x^{2}$ + 26x + 144 - 299 = 0

ii. x = 5

Step-by-step explanation:

The area of the figure = 299 cm²

The figure has a shape of a rectangle, so that;

Area of rectangle = length x width

length of the figure = 18 + x

width of the figure = 8 + x

Area of the figure = (18 + x) x (8 + x)

299 = (18 + x) x (8 + x)

299 = $x^{2}$ + 26x + 144

$x^{2}$ + 26x + 144 - 299 = 0

$x^{2}$ + 26x - 155 = 0

applying the trigonometric formula;

x = (-b ± $\sqrt{b^{2} - 4ac}$ ) ÷ 2a

= (-26 ± $\sqrt{(26)^{2} - 4(1*-155)}$ ) ÷ 2

= (-26 ± $\sqrt{676 +620}$ ) ÷ 2

= (-26 ± $\sqrt{1296}$ ) ÷ 2

= (-26 ± 36) ÷ 2

x = (-26 + 36) ÷ 2 OR x = (-26 -36) ÷ 2

= 10 ÷ 2 OR -62 ÷ 2

= 5 OR -31

Thus, x = 5

5 0

3 years ago