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Murljashka [212]
3 years ago
11

How many times does 32 go into 400

Mathematics
2 answers:
Andrei [34K]3 years ago
7 0
12.5 because 400/32 is 12.5 lol I used a calculator
Vitek1552 [10]3 years ago
3 0

Answer:

3.4

Step-by-step explanation:

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Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
2 years ago
Whats 9+10 ?<br>A)12<br>B)21<br>C)19<br>D)9​
Ostrovityanka [42]

Answer: 21

Step-by-step explanation: (If you're serious it's 19)

4 0
3 years ago
Read 2 more answers
Sorry if you can’t read it but help! If you can
drek231 [11]

Answer:

I believe that it is D

Step-by-step explanation:

A is wrong...

B is wrong (I believe)...

C is wrong...

So D is the only answer choice left.

3 0
2 years ago
Read 2 more answers
True or False: You can be considered a living thing even without a DNA based genetic code,
Illusion [34]

Answer:

True

Step-by-step explanation:

3 0
2 years ago
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The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Fin
NISA [10]

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, \mu=8.04 g

Standard deviation, \sigma=0.08g

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of  machine components

P(Xx_2)=0.03

P(X

=0.03

From z- table we get

P(Z1.88)=0.03

Therefore, we get

\frac{x_1-8.04}{0.08}=-1.88

x_1-8.04=-1.88\times 0.08

x_1=-1.88\times 0.08+8.04

x_1=7.8896

\frac{x_2-8.04}{0.08}=1.88

x_2=1.88\times 0.08+8.04

x_2=8.1904

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

5 0
2 years ago
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