Answer:

General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Property [Addition/Subtraction]:
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Integration
Integration Rule [Reverse Power Rule]: 
Integration Rule [Fundamental Theorem of Calculus 1]: 
Integration Property [Addition/Subtraction]: ![\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%20%7B%5Bf%28x%29%20%5Cpm%20g%28x%29%5D%7D%20%5C%2C%20dx%20%3D%20%5Cint%20%7Bf%28x%29%7D%20%5C%2C%20dx%20%5Cpm%20%5Cint%20%7Bg%28x%29%7D%20%5C%2C%20dx)
U-Substitution
Area of a Region Formula: ![\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A%20%3D%20%5Cint%5Climits%5Eb_a%20%7B%5Bf%28x%29%20-%20g%28x%29%5D%7D%20%5C%2C%20dx)
Step-by-step explanation:
<u>Step 1: Define</u>

<u>Step 2: Identify</u>
<em>Graph the systems of equations - see attachment.</em>
Top Function: 
Bottom Function: 
Bounds of Integration: [-1.529, 1.718]
<u>Step 3: Integrate Pt. 1</u>
- Substitute in variables [Area of a Region Formula]:

- [Integral] Rewrite [Integration Property - Addition/Subtraction]:

- [Right Integral] Integration Rule [Reverse Power Rule]:

- Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:

<u>Step 4: Integrate Pt. 2</u>
<em>Identify variables for u-substitution.</em>
- Set <em>u</em>:

- [<em>u</em>] Basic Power Rule [Derivative Rule - Addition/Subtraction]:

- [Limits] Switch:

<u>Step 5: Integrate Pt. 3</u>
- [Integral] U-Substitution:

- [Integral] Integration Rule [Reverse Power Rule]:

- Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:

- Simplify:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
5/6. fine the common factor of both 4 and 3 and multiple and than simplify.
Answer:
Step-by-step explanation:
3). Definition of midpoint
4). Midpoint theorem ( ≅ parts are = )
7). Division Property of Equality.
8). QR = 5 + <em>2</em> = 7 Substitution x by equal value
9). PQ = 4(<em>2</em>) - 1 = 7 Substitution x by equal value
10). Segment addition postulate
11). Substitution
Answer:

Step-by-step explanation:
Given functions are:

We have to find:
(s.t)(x) => this means we have to multiply the two functions to get the result.
So,

Also we have to find
(s-t)(x) => we have to subtract function t from function s

Also we have to find,
(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x

Putting x = -3

Hence,
