To determine what elements are represented by the electron configuration given above, we need to know the sum of the exponents of each term or subshell involved in the configuration as this represent the atomic number of the element.
Atomic Number Element
<span>1s2 2s2 2p6: 2 + 2 + 6 = 10 neon
1s2 2s2 2p6 3s2 3p3: </span>2 + 2 + 6 + 2 + 3 = <span>15 phosphorus
1s2 2s2 2p6 3s2 3p6 4s1: </span>2 + 2 + 6 + 2 + 6+1 = <span>19 potassium
1s2 2s2 2p6 3s2 3p6 4s2 3d8: 20 + 8 = 28 nickel
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d3: 30 + 6 + 2 +3 = 41 niobium</span>
Answer:
Nothing it'll just stay the same
Explanation:
Is this a joke?
Answer:
I think that it would be a bathtub with water at room temp
Explanation:
There's more water which means more heat
In NaMnO₄, Mn has the highest oxidation number.
The question is incomplete, the complete question is;
Which of the following species contains manganese with the highest oxidation number?
A) Mn
B) MnF₂
C) Mn₃(PO₄)₂
D) MnCl₄
E) NaMnO₄
In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.
1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.
2) For MnF₂;
Mn has an oxidation number of +2
3) For Mn₃(PO₄)₂
Mn has an oxidation number of +2
4) For MnCl₄
Mn has an oxidation number of +4
5) For NaMnO₄
Mn has an oxidation number of +7
Hence in NaMnO₄, Mn has the highest oxidation number.
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