Answer:
12.32 L.
Explanation:
The following data were obtained from the question:
Mass of CH4 = 8.80 g
Volume of CH4 =?
Next, we shall determine the number of mole in 8.80 g of CH4. This can be obtained as follow:
Mass of CH4 = 8.80 g
Molar mass of CH4 = 12 + (1×4) = 12 + 4 = 16 g/mol
Mole of CH4 =?
Mole = mass/Molar mass
Mole of CH4 = 8.80 / 16
Mole of CH4 = 0.55 mole.
Finally, we shall determine the volume of the gas at stp as illustrated below:
1 mole of a gas occupies 22.4 L at stp.
Therefore, 0.55 mole of CH4 will occupy = 0.55 × 22.4 = 12.32 L.
Thus, 8.80 g of CH4 occupies 12.32 L at STP.
Answer:
C. ETC produces 34, Krebs cycle produces 2, glycolysis produces 2.
Explanation:
<em>Glycolysis
</em>
G ⟶ G6P -1ATP
F6P ⟶ FBP -1ATP
2×[1,3-BPG ⟶ 3-PG] <u>+4ATP </u>
Net = 2ATP
<em>Krebs Cycle</em>
2×[succinyl-CoA ⟶ succinate] 2ATP
<em>ETC</em> = 34ATP
the molarity of a solution made by dissolving 5.67 g of potassium chloride in enough water to make 100.0 mL of solution.
Answer:
See explanation and image attached
Explanation:
Now, we have chosen the alkene 1-propene in our example.
In the first reaction of 1-propene with HBr, the reaction proceeds by ionic mechanism leading to the formation of 2-bromo propane.
In the second reaction of 1-propene with the bromine molecule, the first step is the formation of the brominium cation which is a cyclic intermidiate followed by the addition of Br^- yielding the 1,2- dibromopropane product
Answer:
8. littoral I hope it helps