What makes this lever effective?

How does the properties of matter in liquid and gas state allow the Herons fountain to work?

Varvara68 [4.7K]

Answer:

Heron's fountain is an hydraulic machine that works because or the pressure inside of the system. Water will flow from high gravitational potential energy to low gravitational potential energy. The two sides of the system will present different pressure because they have different fluids in it (water and air) and water pressure is higher than gas/air pressure, so it will flow.

It is important to take into account that the pressure in the columns is a function of the height of the fluid (water or air).

Explanation:

The properties of liquid:

- If a liquid is poured into a container, it will adapt to the container's shape

- In a liquid state, the molecules have a kinetic energy higher than in a solid state

- Liquid particles are not arranged in a regular way but they are very close to each other, that's why liquids have a definite volume.

- Force is spread in an even way through a liquid, so the liquid particles are displaced if an object is placed in it.

- Liquids, as solids, can't be compressed

The properies of gas:

- They are everywhere

- Gas molecules are disorganized and have a great deal of space between them

- Gas fill up any container and spread indefinitely

- Gas molecules have a high kinetic energy

- If gas is put under pressure, the space between particles will decrease and collisions between them will increase.

- If the temperature of the gas increases in a container, the pressure will increase; if the temperature decreases, the pressure sill decrease.

- It can be compressed

- Gas has no definite volume nor definite shape.

8 0

2 years ago

Answer this question:

almond37 [142]

Answer:

Meteorologists look at data help from the computer about temperature, pressure, humidity, and wind speed, among many other data points to try and accurately predict the weather.

5 0

2 years ago

10 POINTS

Snowcat [4.5K]

E=hc/λ =6.626×10^-34×3 ×10^8 / 3×10^7 × 10^-9 = 6.626×10 ^-24J.

7 0

2 years ago

The vapor pressure of ethanol at its normal boiling point would be

Galina-37 [17]

The normal boiling point of ethanol is 78.4 degrees C and, at thistemperature, the vapor pressure is 101325 Pascals (Pa) or 760manometric units

thx hope this helped bye.

4 0

3 years ago

7.00 of Compound x with molecular formula C3H4 are burned in a constant-pressure calorimeter containing 35.00kg of water at 25c.

beks73 [17]

Answer:

$\Delta H_{f,C_3H_4}=276.8kJ/mol$

Explanation:

Hello!

In this case, since the equation we use to model the heat exchange into the calorimeter and compute the heat of reaction is:

$\Delta H_{rxn} =- m_wC_w\Delta T$

We plug in the mass of water, temperature change and specific heat to obtain:

$\Delta H_{rxn} =- (35000g)(4.184\frac{J}{g\°C} )(2.316\°C)\\\\\Delta H_{rxn}=-339.16kJ$

Now, this enthalpy of reaction corresponds to the combustion of propyne:

$C_3H_4+4O_2\rightarrow 3CO_2+2H_2O$

Whose enthalpy change involves the enthalpies of formation of propyne, carbon dioxide and water, considering that of propyne is the target:

$\Delta H_{rxn}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{f,C_3H_4}$

However, the enthalpy of reaction should be expressed in kJ per moles of C3H4, so we divide by the appropriate moles in 7.00 g of this compound:

$\Delta H_{rxn} =-339.16kJ*\frac{1}{7.00g}*\frac{40.06g}{1mol}=-1940.9kJ/mol$

Now, we solve for the enthalpy of formation of C3H4 as shown below:

$\Delta H_{f,C_3H_4}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{rxn}$

So we plug in to obtain (enthalpies of formation of CO2 and H2O are found on NIST data base):

$\Delta H_{f,C_3H_4}=3(-393.5kJ/mol)+2(-241.8kJ/mol)-(-1940.9kJ/mol)\\\\\Delta H_{f,C_3H_4}=276.8kJ/mol$

Best regards!

7 0

2 years ago