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3 years ago

How many times larger is 70 than 7

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

8 0

Answer:

Step-by-step explanation:

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Write the numeral for fifty million and sixty thousand

marishachu [46]

500060 is the answer

8 0

3 years ago

Read 2 more answers

Given a right ?ABC, where AB = 4.5 cm, BC = 7.794 cm, and AC = 9 cm, sketch the triangle below, and find the measure m?C in degr

Ksju [112]

Answer:

The measure of angle C is $30\°$

The draw in the attached figure

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABC

The sine of angle C is equal to divide the opposite side to angle C by the hypotenuse

$sin(C)=\frac{AB}{AC}$

substitute the values

$sin(C)=\frac{4.5}{9}$

$C=arcsin(\frac{4.5}{9})=30\°$

5 0

3 years ago

Which number should.be added to the data so that the range of the data is 31? 54,72,64,57

Sergio039 [100]

Answer: 41 or 85

<u>Step-by-step explanation:</u>

Range is the difference between the largest number and the smallest number.

The largest number is 72. 72 - 31 = 41

The smallest number is 54. 54 + 31 = 85

Adding either ONE of those numbers will result in a range of 31.

3 0

3 years ago

+8+-9+-2 on a number line

Zarrin [17]

Hi there! I can help you! 8 + (-9) + (-2). When adding negative integers, you have to subtract. 8 - 9 is -1 and -1 - 2 is -3. You would have to start at 8 and go to the left 11 times to land on -3. The sum to the problem is -3.

3 0

3 years ago

An extremely large sink hole has opened up in a field just outside of the city limits. It is difficult to measure across the sin

abruzzese [7]

Triangle ABC and triangle DCE are congruent, so line DE = line AB

Use the cosine rule to find angle ACB
$52.2^{2}= 50^{2}+ 70^{2}-(2*50*70*cos(ACB))$
$2724.84=7400-(7000cos(ACB))$
$2724.84-7400=-7000cos(ACB)$
$-4675.16=-7000cos(ACB)$
$\frac{4675.16}{7000}=cos(ACB)$
$Angle ACB= cos^{-1} ( \frac{4675.16}{7000})$
Angle ACB = 48.1°

5 0

3 years ago