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Dominik [7]
3 years ago
15

HElp pls for majior brainlest and points

Mathematics
2 answers:
dimulka [17.4K]3 years ago
8 0

Answer:

i think its 4-3r=1.

Step-by-step explanation:

i hope i got it right so you can make some a's

riadik2000 [5.3K]3 years ago
5 0

Answer:

4 -3r (B)

w (A)

3 (A)

8 (B)

2 (B)

Explanation:

Expression = (Number, Math Operator, Number)

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An object is thrown upward from the top of 96​-foot building with an initial velocity of 80 feet per second. The height h of the
stiks02 [169]

The function of the object height is an illustration of a projectile motion

The object will never hit the ground

<h3>How to determine when the object hits the ground?</h3>

The function is given as:

h=16t^2+80t+96.

When the object hits the ground, h = 0

So, we have:

16t^2+80t+96 = 0

Divide through by 16

t^2+5t+6 = 0

Expand

t^2 + 3t + 2t + 6 = 0

Factorize

t(t + 3) + 2(t + 3) = 0

Factor out t + 3

(t + 2)(t + 3) = 0

Solve for t

t = -2 or t = -3

The time (t) cannot be negative.

Hence, the object will never hit the ground

Read more about projectile motion at:

brainly.com/question/1130127

5 0
2 years ago
Congruent triangles pls help
Harrizon [31]
Congruent triangle are the same shape and same size exactly
8 0
3 years ago
If each cube has edges .5 inches long, what is the volume of the prism?
Gre4nikov [31]
.20 is the correct answer
6 0
3 years ago
Read 2 more answers
Money Flow  The rate of a continuous money flow starts at $1000 and increases exponentially at 5% per year for 4 years. Find the
77julia77 [94]

Answer:

Present value =  $4,122.4

Accumulated amount = $4,742

Step-by-step explanation:

Data provided in the question:

Amount at the Start of money flow = $1,000

Increase in amount is exponentially at the rate of 5% per year

Time = 4 years

Interest rate = 3.5%  compounded continuously

Now,

Accumulated Value of the money flow = 1000e^{0.05t}

The present value of the money flow = \int\limits^4_0 {1000e^{0.05t}(e^{-0.035t})} \, dt

= 1000\int\limits^4_0 {e^{0.015t}} \, dt

= 1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4

= 1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]

= 1000 × [70.7891 - 66.6667]

= $4,122.4

Accumulated interest = e^{rt}\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t}} \, dt

= e^{0.035\times4}\times4,122.4

= $4,742

8 0
3 years ago
Write the coefficient of a in 7 a​
Arturiano [62]

Given:

The term is 7a.

To find:

The coefficient of "a" in the given term "7a"​.

Solution:

In the product of a number and a variable, the number is called the coefficient of that variable.

In the expression "7a", the number is "7" and the variable is "a". It means the number 7 is the coefficient of "a".

Therefore, the coefficient of "a" in the given term "7a" is 7​.

8 0
2 years ago
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