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allsm [11]
4 years ago
7

hi can someone help plz im too confused....Describe how mass and distance affect gravitational force.

Physics
2 answers:
skelet666 [1.2K]4 years ago
5 0
It affects how fast a object travels when falling being thro or even rowed

RUDIKE [14]4 years ago
4 0
Mass is something that weighs something down . Gravitational pull is when it is being pulled by something else away or towards ? Did it help? Thanks I hope I helped you a lot
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An egg is dropped from the top of the band hall. if the band hall is 25 m tall, determine the time it takes the egg to hit the f
Vera_Pavlovna [14]

Answer:

2.26 s

Explanation:

The following data were obtained from the question:

Height (h) = 25 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =..?

The time taken for the egg to hit the floor can be obtained as illustrated below:

h = ½gt²

25 = ½ × 9.8 × t²

25 = 4.9 × t²

Divide both side by 4.9

t² = 25 / 4.9

Take the square root of both side

t = √(25 / 4.9)

t = 2.26 s

Thus, it will take 2.26 s for the egg to hit the floor.

7 0
3 years ago
Which of these is an effect of gravity?
castortr0y [4]

Answer:

(A)

A cup placed on a table won't float away

3 0
3 years ago
A resistance is added in parallel to a 470 Ω resistance to give an effective resistance of 330 Ω. What is the approximate value
saw5 [17]
I think its c on the test I had
4 0
4 years ago
Suppose a ball is dropped from some height and 2 seconds later another ball is dropped.
QveST [7]

Answer:

It will never pass, because things fall at the same time, if there are no outside fource or other different like shape, gravity…

8 0
3 years ago
PART ONE
GenaCL600 [577]

Answer:

1. F = 45,458.17 N

2. P = 12,800,000 W

Explanation:

Part 1. The thrust force is the sum of the forces on the air and on the fuel.

For the air, 107 kg of air is accelerated from 281 m/s to 679 m/s in 1 second.

F = ma

F = (107 kg) (679 m/s − 281 m/s) / (1 s)

F = 42,586 N

For the fuel, 4.23 kg of fuel is accelerated from 0 m/s to 679 m/s in 1 second.

F = ma

F = (4.23 kg) (679 m/s − 0 m/s) / (1 s)

F = 2,872.17 N

So the thrust on the jet is:

F = 42,586 N + 2,872.17 N

F = 45,458.17 N

Rounded to three significant figures, the force is 45,500 N.

Part 2. Power = work / time, and work = force × distance, so:

Power = force × distance / time

Power = force × velocity

P = (45,458.17 N) (281 m/s)

P = 12,773,745.77 W

Rounded to three significant figures, the power is 12,800,000 W.

7 0
3 years ago
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