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zaharov [31]
3 years ago
14

An ant walks 2 m in a straight line over a period of 40 s. What is the average speed of the ant?

Physics
1 answer:
BigorU [14]3 years ago
4 0

Answer:

speed is equal to distance/time

so 2m/40s

=0.05

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A diver is swimming underneath an oil slick with a thickness of 200 nm and an index of refraction of 1.50. A white light shines
Tcecarenko [31]

Answer:

Explanation:

thickness of oil t = 200 nm

index of refraction μ = 1.5

For transmitted light :---

path difference = 2μ t

For constructive interference

path difference = n λ , λ is wavelength  of light

2μ t = n λ

λ = 2μ t /  n

For longest λ , n = 1

λ = 2μ t

= 2 x 1.5 x 200 nm

= 600 nm

Wavelength in water

= 600 / refractive index of water

= 600 / 1.33

= 451.1 nm Ans

4 0
4 years ago
Suppose you buy a pair of shoes. They come in a box. You take the shoes
Olin [163]

Answer:

unchanged

Explanation:

the box itself has same mass and volume with or without the shoes

4 0
3 years ago
Which of the following statements it's true about Sir isaac Newton
krek1111 [17]
The legend is that he discovered gravity when an apple feel on his head. I don’t know what the true story is, but that’s what I’ve heard so maybe A??
Although, I’m pretty sure it could also be C
So... between A and C, however, I don’t want you to get it wrong so I would recommend getting another opinion
Hope this helps!
5 0
3 years ago
Read 2 more answers
A 3-kilogram ball is accelerated from rest to a speed of 10 m/sec. What is the ball's change in momentum?
valentina_108 [34]
Change in Momentum =  mv - mu.

u = 0, v = 10 m/s.  Note ball accelerated from rest, so initial velocity = 0. u =0

Change in Momentum =  mv - mu = 3*10 - 3*0 =30.

Change in Momentum = 30 kgm/s.

4 0
3 years ago
Read 2 more answers
Given: G = 6.67259 × 10−11 N m2 /kg2 . A 438 kg geosynchronous satellite orbits a planet similar to Earth at a radius 1.94 × 105
photoshop1234 [79]

Answer:

449.37412 N

Explanation:

G = Gravitational constant = 6.67259 × 10⁻¹¹ m³/kgs²

m = Mass of satellite = 438 kg

M = Mass of planet

T = Time period of the satellite = 24 h

r = Radius of planet = 1.94\times 10^8\ m

The time period of the satellite is given by

T=2\pi\sqrt{\frac{r^3}{GM}}\\\Rightarrow M=4\pi^2\frac{r^3}{T^2G}\\\Rightarrow M=4\pi^2\times \frac{(1.94\times 10^8)^3}{(24\times 3600)^2\times 6.67259\times 10^{-11}}\\\Rightarrow M=5.78686\times 10^{26}\ kg

The gravitational force is given by

F=G\frac{Mm}{r^2}\\\Rightarrow F=6.67259\times 10^{-11}\times \frac{5.78686\times 10^{26}\times 438}{(1.94\times 10^8)^2}\\\Rightarrow F=449.37412\ N

The force acting on this satellite is 449.37412 N

3 0
3 years ago
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