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Mama L [17]
3 years ago
8

This diagram shows two different forces acting on a skateboarder. The

Physics
2 answers:
algol133 years ago
4 0

Answer:

Option A. 0.36 m/s to the left

Explanation:

From the question given above, the following data were obtained:

Force resistance (Fᵣ) = 55.2 N

Applied force (Fₐ) = 31.8 N

Mass (m) = 65.2 kg.

Acceleration (a) =?

Next, we shall determine the net force acting on the skateboarder. This can be obtained as illustrated below:

Force resistance (Fᵣ) = 55.2 N

Applied force (Fₐ) = 31.8 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₐ

Fₙ = 55.2 – 31.8

Fₙ = 23.4 N to the left

Finally, we shall determine the acceleration of the skateboarder. This can be obtained as follow:

Mass (m) = 65.2 kg.

Net force (Fₙ) = 23.4 N to the left

Acceleration (a) =?

F = ma

23.4 = 65.2 × a

Divide both side by 65.2

a = 23.4 / 65.2

a = 0.36 m/s

Since the net force acting on the skateboarder is to the left. Therefore, the acceleration of the stakeholder will also be towards the left (i.e 0.36 m/s to the left)

guapka [62]3 years ago
4 0

Answer:

A. 0.36 m/s to the left

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