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bonufazy [111]
3 years ago
8

Suppose a ball is dropped from some height and 2 seconds later another ball is dropped.

Physics
1 answer:
QveST [7]3 years ago
8 0

Answer:

It will never pass, because things fall at the same time, if there are no outside fource or other different like shape, gravity…

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Ionic compounds can be readily dissolved in water because the high dielectric constant of water screens and decreases the ______
PSYCHO15rus [73]

Answer: Electrostatic force

Explanation :

Ionic compounds can be readily dissolved in water because of the high dielectric constant of water screens and decrease the Electrostatic force between the oppositely charged ions.

Since water is a polar molecule and has a high valued dielectric constant. Water makes a bond with ions when dissolved and reduces the electrostatic forces that hold in a solid structure.

8 0
3 years ago
An lc circuit oscillates at a frequency of 2000 Hz. What will the frequency be if the inductance is quadrupled?
Irina-Kira [14]
<h2>Answer:</h2>

An LC circuits if formed by an inductor and a capacitor. The charge on the capacitor and the current through the inductor both vary sinusoidally with time. Also, energy is transferred between magnetic energy in the inductor and electrical energy in the  capacitor. But <em>what happens with the frequency if the inductance is quadrupled? </em>that is, if initially the inductance is L and the frecuency f=2000Hz if now L_{New}=4L What will the frequency be? Well, we know that the frequency, inductance and capacitance are related as:

f=\frac{1}{2\pi}\sqrt{\frac{1}{LC}}

and this equals 2000Hz. If now L is quadrupled:

f_{1}=\frac{1}{2\pi}\sqrt{\frac{1}{4LC}}=\frac{1}{2\pi}\sqrt{\frac{1}{4}}\sqrt{\frac{1}{LC}} \\ \\ \therefore f_{1}=(\frac{1}{2})\frac{1}{2\pi}\sqrt{\frac{1}{LC}} \\ \\ \\ Since \ f=\frac{1}{2\pi}\sqrt{\frac{1}{LC}} \ then: \\ \\ f_{1}=\frac{1}{2}f \therefore f_{1}=\frac{2000}{2} \\ \\ \therefore \boxed{f_{1}=1000Hz}

<em>Finally, if L is quadrupled the frequency is half the original frequency and equals 1000Hz</em>

3 0
3 years ago
A solid wood door 1.00 m wide and 2.00 m high is hinged along one side and has a total mass of 40.0 kg. Initially open and at re
xxTIMURxx [149]

Answer:

The final angular speed is 0.223 rad/s

Explanation:

By the conservation of angular moment:

ΔL=0

L₁=L₂

L₁ is the initial angular moment

L₂ is the final angular moment

L₁ is given by:

L_1=L_{door} + L_{mud}

As the door is at rest its angular moment is zero and the angular moment of mud can be considered as a point object, then:

L_1= L_{mud}= mvr

where

r is the distance from the support point to the axis of rotation (the mud hits at the center of the door; r=0.5 m)

v is the speed

m is the mass of the mud

L₂ is given by:

L_2= (I_{door} + I_{mud}) \omega_f

ωf is the final angular speed

The moment of inertia of the door can be considered as a rectangular plate:

I_{door}=\frac{1}{3}MW^2

M is the mass of the door

W is the width of the door

The moment of inertia of the mud is:

I_{mud}=mr^2

Hence,

L_1=L_2\\mvr= (I_{door} + I_{mud}) \omega_f\\\omega_f=\frac{mvr}{I_{door} + I_{mud}} \\\omega_f=\frac{mvr}{I_{door} + I_{mud}}

\omega_f=\frac{0.5kg \times 12m/s \times 0.5m}{\frac{1}{3}40kg(1m)^2+0.5kg \times (0.5m)^2}

\omega_f=0.223 \frac{rad}{s}

6 0
4 years ago
A 120 V potential difference is applied to a space heater that dissipates 674 W during operation. (a) What is its resistance dur
Annette [7]

Answer:

(a) 21.36 ohms

(b) 5.62 A

Explanation:

Parameters given:

Potential difference, V = 120 V

Power, P = 674 W

(a) Power is given as:

P = V²/R

Where R is resistance

=> R = V²/P

R = 120²/674

R = 14400/674

R = 21.36 ohms

(b) Power is also given as:

P = I*V

Where I = Current (time rate of flow of Electric charge)

=> I = P/V

I = 674/120

I = 5.62 A

6 0
3 years ago
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Scientists develop knowledge by making about the natural world that may lead to a scientific question. A scientific question may
sladkih [1.3K]
Scientists make hypothesis and do experiments
5 0
3 years ago
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