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Vesna [10]
3 years ago
12

A salesman sold twice as much pears in the afternoon than in the morning. If he sold 360 kilograms of pears that day, how many k

ilograms did he sell in the morning and how many in the afternoon?, Make sure you show your work!
I'LLGIVE YOU BRAINLIEST!!!!!!!
Mathematics
2 answers:
Dahasolnce [82]3 years ago
8 0

Answer:

165

Step-by-step explanation:

Khan academy

Setler [38]3 years ago
5 0

Answer:

The salesman sold 120 kg of pears in the morning and 240 kg of pears in the afternoon.

Step-by-step explanation:

Let x be the amount of pears sold in the morning.

2x, amount of pears sold in the afternoon.

x + 2x = 360 kg

Solution:

x + 2x = 360 kg

3x = 360 kg

3x/3 = 360 kg/3

x = 120

He sold 120 kg of pears in the morning.

2x = 2(120 kg) = 240 kg

He sold 240 kg of pears in the afternoon.

Final Answer:

The salesman sold 120 kg of pears in the morning and 240 kg of pears in the afternoon.

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garik1379 [7]

Answer:

3.24

Step-by-step explanation:

You would use the two fonts given to find the scale factor.

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What is an equation in point-slope form of the line that passes through (-7, 1) and (-3, 9)?
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writing the linear equation can be used by any any of those coordinates that are given

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For the algorithm below, compute the number of multiplications performed, as well as the final value of s. p ← 1 s ← 0 for i is
enot [183]
<span>p ← 1

s ← 0

for i is in {1, 2, 3, 4}
      do p ← p · 3
           s ← s + p

n = 1 => first iteration

               p = 1 * 3 = 3
               s = 0 + 3 = 3

number of multiplications ---> 1

n = 2
             p = 3 * 3 = 9
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number of multiplications ----> 1 + 1 = 2

n = 3
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n = 4
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Answer: number of mujltiplications: 4
final value of s: s = 120.

</span>
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4 years ago
24times 2-8+ Four to the second powerdivided by 8 -6
allochka39001 [22]

Answer:

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3 years ago
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The sides of ∆ABC are 30 units, 40 units, and 60 units long. The corresponding sides of ∆XYZ are r times as long as the sides of
san4es73 [151]

Part a) Find the expression that gives the perimeter of ∆XYZ

we know that

Perimeter of triangle ABC is equal to

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In this problem ∆ABC and ∆XYZ are similar triangles

the scale factor is equal to r

so

scale\ factor=r \\ \\ scale\ factor=\frac{perimeter\ triangle\  XYZ}{perimeter\  triangle\  ABC}  \\ \\ perimeter\ triangle\  XYZ=perimeter\  triangle\  ABC*scale factor\\ \\ perimeter\ triangle\  XYZ=130*r

therefore

the answer Part a) is

The expression that gives the perimeter of ∆XYZ is 130*r\ units

Part b) Find the expression that gives the area of ∆XYZ

we know that

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scale\ factor=r \\ \\ scale\ factor^{2}=\frac{Area\ triangle\  XYZ}{Area\  triangle\  ABC}  \\ \\ Area\ triangle\  XYZ=Area\  triangle\  ABC*scale factor^{2}\\ \\ Area\ triangle\  XYZ=n*r^{2}\ units^{2}

therefore

the answer Part b) is

The expression that gives the Area of ∆XYZ is n*r^{2}\ units^{2}

3 0
3 years ago
Read 2 more answers
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