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VladimirAG [237]

3 years ago

7

There are many campers at Camp Lots of Fun. This morning, 4 kids went home sick. Of the remaining campers, 18 kids went hiking a

nd the other 41 kids spent the day swimming. How many kids started the day at Camp Lots of Fun?

1 answer:

erastovalidia [21]3 years ago

8 0

Answer:

63

Step-by-step explanation:

You would add 41 + 18 + 4, which obviously gets you 63. Hope this helped!

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Jing makes a cut through a block of butter, as shown. What are the

levacccp [35]

Answer: C) 4 x 3 cm

Step-by-step explanation:

The only dimension affected by the cut was 5, because the cut was perfectly parallel to the 4x3 face.

6 0

3 years ago

Joe and Linda have the opportunity to purchase a new home. The house in Glen Oaks is currently worth $250,000 but is predicted t

Dmitry [639]

You can work out the percentage change and that would help you work out the rate of appreciation :)

The formula is ((new value - old value)/old value) * 100.

So you do $\frac{270,000 - 250,000}{250,000} \times 100 = 8\%$

Therefore the rate of appreciation is 8% p/a.

7 0

3 years ago

At me farmers market, bananas coast $0.80 per pound.At another farmers market, bananas are sold in 5-pound bags for $4.50 per ba

Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

At the first place is better because

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$4.5 / 5 = $0.9

Is more expensive in the another place

5 0

3 years ago

What is the formula for finding the final balance of an account that earns interest compounded annually? State what each variabl

Schach [20]

C=P[(1+r)^n-1]
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5 0

3 years ago

If x^2y-3x=y^3-3, then at the point (-1,2), (dy/dx)?

zavuch27 [327]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2866883

_______________

   dy
Find —— for an implicit function:
    dx

x²y – 3x = y³ – 3

First, differentiate implicitly both sides with respect to x. Keep in mind that y is not just a variable, but it is also a function of x, so you have to use the chain rule there:

$\mathsf{\dfrac{d}{dx}(x^2 y-3x)=\dfrac{d}{dx}(y^3-3)}\\\\\\
\mathsf{\dfrac{d}{dx}(x^2 y)-3\,\dfrac{d}{dx}(x)=\dfrac{d}{dx}(y^3)-\dfrac{d}{dx}(3)}$

Applying the product rule for the first term at the left-hand side:

$\mathsf{\left[\dfrac{d}{dx}(x^2)\cdot y+x^2\cdot \dfrac{d}{dx}(y)\right]-3\cdot 1=3y^2\cdot \dfrac{dy}{dx}-0}\\\\\\
\mathsf{\left[2x\cdot y+x^2\cdot \dfrac{dy}{dx}\right]-3=3y^2\cdot \dfrac{dy}{dx}}$

   dy
Now, isolate —— in the equation above:
   dx

$\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3=3y^2\cdot \dfrac{dy}{dx}}\\\\\\
\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3-3y^2\cdot \dfrac{dy}{dx}=0}\\\\\\
\mathsf{x^2\cdot \dfrac{dy}{dx}-3y^2\cdot \dfrac{dy}{dx}=-\,2xy+3}\\\\\\
\mathsf{(x^2-3y^2)\cdot \dfrac{dy}{dx}=-\,2xy+3}$

$\mathsf{\dfrac{dy}{dx}=\dfrac{-\,2xy+3}{x^2-3y^2}\qquad\quad for~~x^2-3y^2\ne 0}$

Compute the derivative value at the point (– 1, 2):

x = – 1 and y = 2

$\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{-\,2\cdot (-1)\cdot 2+3}{(-1)^2-3\cdot 2^2}}\\\\\\
\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{4+3}{1-12}}\\\\\\
\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{7}{-11}}\\\\\\\\ \therefore~~\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=-\,\dfrac{7}{11}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>implicit function derivative implicit differentiation chain product rule differential integral calculus</em>

6 0

3 years ago