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VladimirAG [237]

3 years ago

7

There are many campers at Camp Lots of Fun. This morning, 4 kids went home sick. Of the remaining campers, 18 kids went hiking a

nd the other 41 kids spent the day swimming. How many kids started the day at Camp Lots of Fun?

1 answer:

erastovalidia [21]3 years ago

8 0

Answer:

63

Step-by-step explanation:

You would add 41 + 18 + 4, which obviously gets you 63. Hope this helped!

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Aleks04 [339]

We see that they are made up of identical squares, meaning that each side of each square is the same length. There are 12 square sides that make up the perimeter of A, so we can do 72/12 which is 6. We see there are ten total square lengths on the perimeter of b, so we can do 6 times 10 which is 60 cm. That’s your perimeter.

7 0

3 years ago

Select all expressions that are equivalent to 2x+2+4x-2x-5 **

Umnica [9.8K]

The answer that you’re looking for is B & D

6 0

3 years ago

Simplify:9-1÷2÷27^2÷3

sammy [17]

<u>First let's calculate the exponents.</u>

$27^2 : 729 = 9-1\div \:2\div \:729\div \:3$

<u>Now we should multiply and divide.</u>

<u /> $1\div2\div729\div3:\frac{1}{4374} = 9-\frac{1}{4374}$ <u />

<u>Now we should add and subtract.</u>

<u /> $9-\frac{1}{4374} :\frac{39365}{4374} = \frac{39365}{4374}$ <u />

<u>Convert the improper fractions into mixed numbers.</u>

<u /> $8\frac{4373}{4374}$ <u />

<u />

<u>Answer : </u>

<u /> $8\frac{4373}{4374}$ <u />

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5 0

3 years ago

D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

3 years ago

?????????????? help out

dimaraw [331]

Answer:

20 degrees C

Step-by-step explanation:

You would substitute the F with 68 since it is 68 degrees F. Then you would solve the equation. (Subtract 32 from 68=36; multiply 36 by 5/9=20)

5 0

3 years ago