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Zinaida [17]
3 years ago
12

How many water molecules (H2O) can be produced from 6 molecules of hydrogen gas (white) reacting with 6 molecules of oxygen gas

(red)? Which reactant is the limiting reactant?
Chemistry
2 answers:
Vladimir79 [104]3 years ago
5 0
I think you can only have 3 water molecules because you need 2 hydrogen molecules in every water molecule and you have 6 hydrogen molecules so 6/2=3 and the reactant that is limited would be hydrogen since it limits the amount of water molecules you can have
Elza [17]3 years ago
3 0

<u>Answer:</u> The hydrogen gas is the limiting reagent and 6 molecules of water are produced.

<u>Explanation:</u>

We are given:

Molecules of hydrogen gas = 6 molecules

Molecules of oxygen gas = 6 molecules

The chemical equation for the reaction of hydrogen gas and oxygen gas follows:

2H_2+O_2\rightarrow 2H_2O

By Stoichiometry of the reaction:

2 molecules of hydrogen gas reacts with 1 molecule of oxygen gas

So, 6 molecules of hydrogen gas will react with = \frac{1}{2}\times 6=3 molecules of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 molecules of hydrogen gas produces 2 molecules of water

So, 6 molecules of hydrogen gas will produce = \frac{2}{2}\times 6=6 molecules of water

Hence, the hydrogen gas is the limiting reagent and 6 molecules of water are produced.

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The energy change ∆H associated with the reaction NBr3(g) + 3 H2O(g) → 3 HOBr(g) + NH3(g) is +81 kJ. NBr3 is arranged with all o
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Answer:

155 kJ

Explanation:

The energy change will be the energy of the reactants less the energy of the products. And the energy of each compound is the sum of the energy of their bonds. Let's call y the N-Br strength.

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