Answer is: hydrogen bonds.
Hydrogen bond is an electrostatic attraction between two polar groups that occurs when a hydrogen atom (H), covalently bound to a highly electronegative atom such as flourine (F), oxygen (O) and nitrogen (N) atoms.
According to the principle of base pairing hydrogen bonds could form between adenine and thymine (two hydrogen bonds between this nucleobases) and guanine and cytosine (three hydrogen bonds between this nucleobases).
Adenine and guanine are purine derivatives and thymine and cytosine are pyrimidine derivates.
The molecular formula of the compound that we are required to find is the compound C4H8O8
<h3>What is empirical formula?</h3>
The empirical formula of a compound is a formula that shows the ratio of each atom present in the compound. We will start by dividing each mass with the relative atomic mass of the atom.
Carbon - 48.38 g/12 Hydrogen - 6.74 g/1 Oxygen - 53.5 g/16
Carbon - 4 Hydrogen - 6.74 Oxygen - 8.9
Dividing through by the lowest ratio;
Carbon - 4/4 Hydrogen - 6.74/4 Oxygen 8.9/4
Carbon 1 Hydrogen 2 Oxygen 2
The empirical formula is CH2O2.
To obtain the molecular formula; brainly.com/question/11588623
[12 + 2 + 32]n = 180
n = 180/[12 + 2 + 32]
n =4
The compound C4H8O8
Learn more about empirical formula:
Answer:
Explanation:
Not Many
1 mol of CO has a mass of
C = 12
O = 16
1 mol = 28 grams.
1 mol of molecules = 6.02 * 10^23
x mol of molecules = 3.14 * 10^15 Cross multiply
6.02*10^23 x = 1 * 3.14 * 10^15 Divide by 6.02*10^23
x = 3.14*10^15 / 6.02*10^23
x = 0.000000005 mols
x = 5*10^-9
1 mol of CO has a mass of 28
5*10^-9 mol of CO has a mass of x Cross Multiply
x = 5 * 10^-9 * 28
x = 1.46 * 10^-7 grams
Answer: there are 1.46 * 10-7 grams of CO if only 3.14 * 10^15 molecules are in the sample
Water levels tend to drop in dry weather because of evaporation. The hot temperatures will cause the water to achieve its gaseous state and go up into the atmosphere.
Answer:
<h2>The Alkali metal halide may precipitate or there may be no change at all</h2>
Explanation:
Alkali metal cations are positively charged. Halogen anions are negatively charged. When a solution of Alkali metal cations is added to a solution of Halogen anions, there are two possibilities :
- The alkali metal halide( salt formed from reation of the two ions) may precipitate if the Ionic product is higher than the Solubility product.
- However, if it can remain in the solution, it will remain so. No chemical changes happen with respect to these both ions. Nothing willl happen.
There is no reaction happening in either of the cases because both species are already in ionic form before addition, hence they continue to be in this form.
