Temperature and Pressure One way to increase the solubility of a gas is to decrease the temperature of the liquid. The solubility of a gas in a liquid is usually temperature dependent, although it depends on the particular combination of which gas and which liquid. Usually the solubility of a gas goes down with increasing temperature (think of warm carbonated beverages going flat).
<span>The other way to increase the solubility is to increase the pressure of the gas. The higher the pressure of the gas above the liquid, the more will dissolve. Again, think of a carbonated beverage: when it is sealed it doesn't go flat because it is under pressure, but when open to air, it will go flat. </span>
Answer:
4N2H4(2) + 2N204 (1) --> 6N2 (g) + 8H20 (g), AHO-2098 kJ
Explanation:
2N2H4(2) + N204 (1) --> 3N2 (g) + 4H20 (g),AHO-1049 kJ
when 6 mol of nitrogen are formed?
The ratio of Nitrogen in the previous therrmochemical equation to when 6 mol f nitrogen are formed is 2; 6/3 = 2.
So to get the new thermoochemical equation, multiply all parameters in the given equation by 2.
We have;
4N2H4(2) + 2N204 (1) --> 6N2 (g) + 8H20 (g), AHO-2098 kJ
Answer:
All of the above.
Explanation:
Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances.
This process is not reversible and a change of energy that is sometimes heat is given off.
Answer: Derived lipids:
Hydrolysis product of simple and compound lipids is called derived lipids. They include fatty acid, glycerol, sphingosine and steroid derivatives. Steroid derivatives are phenanthrene structures that are quite different from lipids made up of fatty acids.
Explanation:
0,35 kmol/m³ = 0,35 mol/dm³ = 0,35 mol/L
175 mL = 0,175 L
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C = n/V
n = 0,35×0,175
n = 0,06125 mol
mCa(NO₃)₂: 40+(14×2)+(16×6) = 164 g/mol
1 mol --------- 164g
0,06125 ---- X
X = 10,045g
To prepare 175 mL of 0,35M solution, add 10,045g of calcium nitrate and add water to a volume of 175ml.