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Olenka [21]
3 years ago
13

Please help I have 50 minutes on this quiz!?!

Chemistry
1 answer:
Mariana [72]3 years ago
7 0

Explanation:

put them in where the letters start with

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What is the best way to transfer solid chemicals into a beaker?
gulaghasi [49]
Use a scoop or spatula to transfer the chemical
8 0
4 years ago
A piece of unknown solid substance weighs 437.2 g, and requires 8460 J to increase its temperature from 19.3 °C to 68.9 °C.What
Pachacha [2.7K]

Answer:

0.3832

Explanation:

Givens

m = 437.2 grams

c = ?

delta t = 69.8 - 19.3

H = 8460 J

Formula

H = m*c*Δt

Solution

8460 = 437.2 * c * (69.8 - 19.3)

8460 = 437.2 * c * 50.5

8460 = 22078.6 * c

c = 8460 / 22078,6

c = .3832 J / (oC * gr)

3 0
3 years ago
Watch the animation and identify the correct conditions for forming a hydrogen bond. check all that apply. check all that apply.
OLga [1]
The ch4 molecule exhibits hydrogen bonding.
This statement is false. A CH4 molecule do not have a hydrogen bonding instead it has dipole dipole attraction.

Hydrogen bonding occurs when a hydrogen atom is covalently bonded to an N, O, or F atom.
This would be a true statement. A hydrogen bond is present when an atom of hydrogen shares electrons with O, N or F atom.

A hydrogen bond is equivalent to a covalent bond.
This is a false statement. A hydrogen bond is an intermolecular force of attraction while covalent bond is a intramolecular force. So, they would mean different things.

a hydrogen bond is possible with only certain hydrogen-containing compounds.
This would be true. Without the presence of an hydrogen atom definitely there would be no hydrogen bond.

a hydrogen atom acquires a partial positive charge when it is covalently bonded to an f atom.
This would be true since a HF is a polar molecule.
6 0
4 years ago
Read 2 more answers
Been sick please help with all. missed to much class
DENIUS [597]
I can't see the picture properly so can you make zoomed in pictures for me?
7 0
4 years ago
`I am holding a balloon containing 439 mL of gas over my fireplace. The temperature and pressure of the gas inside the balloon i
Andrew [12]

Answer:

- 0.07 °C

Explanation:

At constant pressure and number of moles, Using Charle's law  

\frac {V_1}{T_1}=\frac {V_2}{T_2}

Given ,  

V₁ = 439 mL  = 0.439 L ( 1 L = 0.001 mL )

V₂ = 0.378 L

T₁ = 317.15 K

T₂ = ?

Using above equation as:

\frac{0.439}{317.15}=\frac{0.378}{T_2}

T_2=\frac{0.378\cdot \:317.15}{0.439}=273.08\ K

The conversion of T(K) to T( °C) is shown below:

T( °C) = T(K) - 273.15  

So, <u>T = 273.08 - 273.15 °C = - 0.07 °C</u>

3 0
4 years ago
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