Answer:
There are many equations for oxidation and reduction, but the most relevant ones are the equations for the half-reactions. In general, the equation for oxidation is:
Oxidation: Reducing Agent + O2 → Oxidizing Agent
And the equation for reduction is:
Reduction: Oxidizing Agent + e- → Reducing Agent
These equations show the transfer of electrons that occurs during oxidation and reduction.
Explanation:
Answer:
Volume of water added = 2.0 L
Explanation:
Initial pH of the solution = 2.7
[H^+] concentration in 2 L solution of sulfuric acid,
![pH = -log[H^+]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH%5E%2B%5D)
![[H^+] = 10^{-pH}\ M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%20%3D%2010%5E%7B-pH%7D%5C%20M)
![[H^+] = 10^{-2.7} = 0.001995\ M = 0.002\ M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%20%3D%2010%5E%7B-2.7%7D%20%3D%200.001995%5C%20M%20%3D%200.002%5C%20M)
Final pH of the solution = 3
Final [H^+] concentration of sulfuric acid,
![[H^+] = 10^{-pH}\ M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%20%3D%2010%5E%7B-pH%7D%5C%20M)
![[H^+] = 10^{-3} = 0.001\ M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%20%3D%2010%5E%7B-3%7D%20%3D%200.001%5C%20M)
Now,



Volume added = Final volume - Initial volume
= 4.0 - 2.0 = 2.0 L
This problem is requiring the balanced chemical equation that takes place when copper hydroxide and potassium sulfate are produced when reacting potassium hydroxide with copper sulfate.
<h3>Balancing chemical equations:</h3>
In chemistry, balancing chemical equations is based on the law of conservation of mass, which demands us to have equal number of atoms on both sides of the chemical equation. This can be accomplished by inserting coefficients in front of the chemical species.
For this particular case, we have potassium hydroxide with copper sulfate on the reactants side, however, copper can be copper (I) or copper (II) as it has 1+ and 2+ as its possible oxidation numbers. In addition, copper hydroxide and potassium sulfate as the products. Hence, we can assume this is all about copper (II) so we can write:

As we can see, potassium, hydrogen and oxygen have two atoms each on the products side, but just one on the reactants side; drawback we can overcome by putting a 2 in front of KOH so as to balance it:

Learn more about balancing chemical equations: brainly.com/question/8062886
Answer:
18 * 10^19 atoms
Explanation:
We must first convert 57.8 mg to grams.
If 1000 mg = 1g
57.8 mg = 57.8/1000 = 57.8 * 10^-3 g
Now;
If 1 gold atom has a mass of 3.27X10^-22 grams
x gold atoms have a mass of 57.8 * 10^-3 g
x = 57.8 * 10^-3 g/3.27X10^-22 g
x = 18 * 10^19 atoms
When non metallic oxide for example SO2 dissolved in water it produces sulphurous acid. SO2 + H2O → H2SO3 When metallic oxide reacts with water it produces Metal hydroxides. Na2O + H2O → 2NaOH