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grandymaker [24]
3 years ago
9

Find the least common multiple of these two expressions. 10v^6y^7 and 6w^4v^5y^3

Mathematics
1 answer:
egoroff_w [7]3 years ago
4 0

10v⁶y⁷    = <u>2</u> * 5 * <u>vvvvv</u>v * <u>yyy</u>yyyy      

6w⁴v⁵y³ = <u>2</u> * 3 * wwww * <u>vvvvv</u> * <u>yyy</u>

GCF: 2v⁴y³

<em>The LCM is the GCF and everything leftover</em>

LCM: 2v⁴y³ * (5 * v * yyyy) * (3 * wwww)

       = (2 * 5 * 3) * (v⁴ * v) * (w⁴) * (y³ * y⁴)

       =        30           v⁵        w⁴        y⁷

Answer: LCM =  30v⁵w⁴y⁷

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To \; find \; domain:\\\\h(t) \geq0\\\\-16t^2+96t \geq  0\\Factoring \; -16t \; in \; the \; left \; side \; of \; the \; inequality\\\\-16t(t-6) \geq  0\\Step \; 1: Find \; Boundary \; Points \; by \; setting \; up \; above \; inequality \; to \; zero.\\\\t(t-6)=0\\Use \; zero \; factor \; property \; to \; solve\\\\t=0 \; (or) \; t = 6\\\\Step \; 2: \; List \; the \; possible  \; solution \; interval \; using \; boundary \; points\\(- \infty,0], \; [0, 6], \& [6, \infty)

Step \; 3:Pick \; test \; point \; from \; each \; interval \; to \; check \; whether \\\; makes \; the \; inequality \; TRUE \; or \; FALSE\\\\When \; t = -1\\-16(-1)(-1-6) \geq  0\\-112 \geq  0 \; FALSE\\(-\infty, 0] \; is \; not \; solution\\Also \; Logically \; time \; t \; cannot \; be \; negative\\\\When \; t = 1\\-16(1)(1-6) \geq  0\\80 \geq  0 \; TRUE\\ \; [0, 6] \; is \; a \; solution\\\\When \; t = 7\\-16(7)(7-6) \geq  0\\-112 \geq  0 \; FALSE\\ \; [6, -\infty) \; is \; not \; solution

Conclusion:

The domain of the function is the time in between 0 to 6 seconds

0 \leq  t \leq  6

The height will be positive in the above interval.

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3 years ago
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