Find the least common multiple of these two expressions. 10v^6y^7 and 6w^4v^5y^3
1 answer:
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Answer:
<h2>The mean decreases, and the median remains the same.</h2>Step-by-step explanation:
Remember that a box plot is made by the quartiles of the distribution, the maximum value and the minimum value. So, from a box plot we can deduct the range, the median and the interquartile range.
In this case, the median remains the same at $9.5 per hour. The median is indicated by the middle line of the box, and you can observe that it doesn't change.
Now, the range of the data set decreases from 7 to 3.
On the other hand, the mean must decrease, because data greater than $11 doesn't exist in the box plot number 2, and the mean is a central measure sensible to those changes.
Therefore, the right answer is <em>The mean decreases, and the median remains the same.</em>
Answer:
0.0159
Step-by-step explanation:
Given that a common practice of airline companies is to sell more tickets for a particular flight than there are seats on the plane, because customers who buy tickets do not always show up for the flight.
Here if X is the no of persons that do not show up, then X is binomial as each trial is independent with p = 0.04 and n =150 (no of tickets sold)
The plane is overbooked if more than 150 show up
i.e. less than 2 do not show up
Hence the probability that the airline overbooked this flight
=
Answer:
636.4 in³
Step-by-step explanation:
Volume of a cone is given by:
where r is the radius of the base of the cone and h is its height.
It is given that, the radius of the base of the cone is, r = 8 in
The height of the cone is, h = 9.5
Thus, the volume of the cone is 636.4 in³