Answer:
There are 70 sheep in the farm.
Step-by-step explanation:
Consider the provided information.
Let c represents the cows, s represents the sheep and p represents the pigs.
The number of cows and the number of sheep are in the ratio 6:5.


The number of sheep and the number of pigs are in the ratio 2:1.


The total number is 189.

Substitute the value of c and p in above.




Hence, there are 70 sheep in the farm.
0.84% of the graduates will receive the tax break
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
Z = x - μ / σ
Z-scores are used to measure how far a measure is from the mean. We find the p-value associated with this Z-score by looking at the z-score table after finding the Z-score. The p-value represents the probability that the measure is smaller than X, which is the percentile of X. The probability of the measure being greater than X is calculated by subtracting 1 from the pvalue.
μ = $55,000 σ = $6,000
This is the pvalue of Z when X = $39,600. So
z = 39600 - 55000 / 6000
z = -2.5
z = -2.5 has a o value of 0.0084
0.84% of the graduates will receive the tax break.
To learn more about similar tax break:
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3÷1470 will be 490 that were sold from the profit
Answer:
x = 4, TU = 22
Step-by-step explanation:
Given that TS bisects TU at Q , then
TQ = QU , substitute values
5x - 9 = 15 - x ( add x to both sides )
6x - 9 = 15 ( add 9 to both sides )
6x = 24 ( divide both sides by 6 )
x = 4
Thus
TU = 5x - 9 + 15 - x = 4x + 6 = 4(4) + 6 = 16 + 6 = 22