Answer:
From the figure shown the coordinates of W'X'Y'Z' are W'(2, 3), X'(6, 3), Y'(6, 4) and Z'(3, 5)
The coordinates of the pre-image that yeilded W'X'Y'Z' according to the rule (-x, -y) can be obtained by changing the signs of the coordinates of W'X'Y'Z'.
Thus, the coordinates of the pre-image that yeilded W'X'Y'Z' are W(-2, -3), X(-6, -3), Y(-6, -4) and Z(-3, -5).
Therefore, the correct graph is graph c.
(Need to update complete question)
Answer:
Points H, J, G, and K
Step-by-step explanation:
For quadrats the right top is 1
left top is 2
left bottom is 3
right bottom is 4
and it is asking for the forth one so look at the right bottom "square"
G and K are on the line but that still makes them part of a Quadratic Just they get to be part of 2 of them like...
G is 3 and 4
K is 1 and 4
Answer:
Brooooo im stuck on the same one.
Step-by-step explanation:
-8h - 2h^2
f(2)-f(2+h) = -8h - 2h^2
Mark brainliest please
