Answer:
A. (0, -2) and (4, 1)
B. Slope (m) = ¾
C. y - 1 = ¾(x - 4)
D. y = ¾x - 2
E. -¾x + y = -2
Step-by-step explanation:
A. Two points on the line from the graph are: (0, -2) and (4, 1)
B. The slope can be calculated using two points, (0, -2) and (4, 1):
Slope (m) = ¾
C. Equation in point-slope form is represented as y - b = m(x - a). Where,
(a, b) = any point on the graph.
m = slope.
Substitute (a, b) = (4, 1), and m = ¾ into the point-slope equation, y - b = m(x - a).
Thus:
y - 1 = ¾(x - 4)
D. Equation in slope-intercept form, can be written as y = mx + b.
Thus, using the equation in (C), rewrite to get the equation in slope-intercept form.
y - 1 = ¾(x - 4)
4(y - 1) = 3(x - 4)
4y - 4 = 3x - 12
4y = 3x - 12 + 4
4y = 3x - 8
y = ¾x - 8/4
y = ¾x - 2
E. Convert the equation in (D) to standard form:
y = ¾x - 2
-¾x + y = -2
Answer:2,2
Step-by-step explanation:
I remember doing this last year
First you must acknowledge that you are dealing with a line therefore you must write linear equation or linear function in this case.
Linear function has a form of,
Then calculate the slope <em>m</em> using the coordinates of two points. Let say <em>A(x1, y1)</em> and <em>B(x2, y2)</em>,
Now pick a point either <em>A</em> or <em>B</em> and insert coordinates of either one of them in the linear equation also insert the slope you just calculated, I will pick point <em>A</em>.
From here you solve the equation for n,
So you have slope <em>m</em> and variable <em>n</em> therefore you can write down the equation of the line,
Hope this helps.
r3t40
Answer:
B on the first question and A on the 2nd
Step-by-step explanation:
The length can be found using the Pythagorean Theorem...
c^2=a^2+b^2 and in this case:
d^2=(dx^2)+(dy^2)
d^2=(3-7)^2+(12-9)^2
d^2=-4^2+3^2
d^2=16+9
d^2=25
d=5
So the length of AB=5 units.
